在 Java 中匹配非空白 [英] Matching non-whitespace in Java

问题描述

我想检测包含非空白字符的字符串.现在我正在尝试:

I would like to detect strings that have non-whitespace characters in them. Right now I am trying:

!Pattern.matches("\\*\\S\\*", city)

但它似乎不起作用.有没有人有什么建议?我知道我可以修剪字符串并测试它是否等于空字符串，但我宁愿这样做

But it doesn't seem to be working. Does anyone have any suggestions? I know I could trim the string and test to see if it equals the empty string, but I would rather do it this way

推荐答案

你认为正则表达式匹配什么?

What exactly do you think that regex matches?

试试

Pattern p = Pattern.compile( "\\S" );
Matcher m = p.matcher( city );
if( m.find() )
//contains non whitespace

find 方法将搜索部分匹配，而不是完全匹配.这似乎是您需要的行为.

The find method will search for partial matches, versus a complete match. This seems to be the behavior you need.

这篇关于在 Java 中匹配非空白的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！