隐藏和显示小部件的正确方法? [英] Correct way to hide and show widgets?

问题描述

在我的应用程序中，我需要在特定时间显示和隐藏诸如 button 和 textview 之类的小部件.我的做法如下:

In my app, I need to show and hide widgets like button and textview at a certain time. and how I am doing is as the following:

private void hideviews() {
    image.setVisibility(View.GONE); ///ImageView
    title1.setVisibility(View.GONE);///TextView
    title2.setVisibility(View.GONE);///TextView
    title3.setVisibility(View.GONE);///TextView
    title4.setVisibility(View.GONE);///TextView
    title5.setVisibility(View.GONE);///TextView
}

private void showviews() {
    image.setVisibility(View.VISIBLE);
    title1.setVisibility(View.VISIBLE);///TextView
    title2.setVisibility(View.VISIBLE);///TextView
    title3.setVisibility(View.VISIBLE);///TextView
    title4.setVisibility(View.VISIBLE);///TextView
    title5.setVisibility(View.VISIBLE);///TextView

} 

我认为这不是正确的做法.因为我不知道会有多少小部件.非常感谢有关如何正确显示小部件的任何指导.

I don't think this is the correct way to do this. Because I don't know how many widgets there will be. Any guidance on how to correctly show widgets is really appreciated.

推荐答案

制作一个包含所有要显示/隐藏的视图的数组:

Make an array of all the views that you want to show/hide:

View[] views = {image, title1, title2, title3, title4, title5};

然后用它来隐藏它们:

for (View view : views) {
    view.setVisibility(View.GONE);
}

并用它来展示它们:

    for (View view : views) {
        view.setVisibility(View.VISIBLE);
    }

尽管您可以将两个代码部分组合在一个过程中:

although you can combine the 2 code parts in a single procedure:

void fixViews(int state) {
        for (View view : views) {
            view.setVisibility(state);
        }
}

并调用它:

fixViews(View.GONE); 或 fixViews(View.VISIBLE);

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