从可执行文件创建 Windows 服务 [英] Create Windows service from executable

问题描述

给定一个可执行文件，有没有什么快速的方法可以创建一个在启动时启动它的 Windows 服务?

Is there any quick way to, given an executable file, create a Windows service that, when started, launches it?

推荐答案

要从可执行文件创建 Windows 服务，您可以使用 sc.exe:

To create a Windows Service from an executable, you can use sc.exe:

sc.exe create <new_service_name> binPath= "<path_to_the_service_executable>"

exe 的实际路径必须用引号引起来，binPath= 后面必须有一个空格.

You must have quotation marks around the actual exe path, and a space after the binPath=.

可在 Microsoft KB251192 中找到有关 sc 命令的更多信息.

More information on the sc command can be found in Microsoft KB251192.

请注意，它不适用于任何可执行文件:可执行文件必须是 Windows 服务 (即实现 ServiceMain).将非服务可执行文件注册为服务时，您将在尝试启动服务时收到以下错误:

Note that it will not work for just any executable: the executable must be a Windows Service (i.e. implement ServiceMain). When registering a non-service executable as a service, you'll get the following error upon trying to start the service:

错误 1053:服务没有及时响应启动或控制请求.

Error 1053: The service did not respond to the start or control request in a timely fashion.

有些工具可以从任意的非服务可执行文件创建 Windows 服务，请参阅其他答案以获取此类工具的示例.

There are tools that can create a Windows Service from arbitrary, non-service executables, see the other answers for examples of such tools.

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