如何在 Windows 上的 Python 中捕获 SIGINT? [英] How do I capture SIGINT in Python on Windows?

问题描述

(类似于这个问题)

在 Python 2.7 下的 UNIX 上，在 Python 提示符处:

On UNIX under Python 2.7, at the Python prompt:

 >>> import signal
 >>> def handler(signal, frame):
 ...     print 'welcome to the handler'
 ...
 >>> signal.signal(signal.SIGINT, handler)
 <built-in function default_int_handler>

我按 ctrl-c

 >>> welcome to the handler

 >>>

在 Windows 上:

On Windows:

 >>> import signal
 >>> def handler(signal, frame):
 ...     print 'welcome to the handler'
 ...
 >>> signal.signal(signal.SIGINT, handler)
 <built-in function default_int_handler>

按下 ctrl-c 后:

Upon pressing ctrl-c:

 >>>
 KeyboardInterrupt
 >>>

我可以验证 handler 是否安装在 Python 端作为 SIGINT 的处理程序(调用 signal.signal 第二个计时器返回我的 handler>).如何在 Windows 上捕获 SIGINT?

I can verify that handler is being installed Python-side as the handler for SIGINT (calling signal.signal a second timer returns my handler). How can I capture SIGINT on Windows?

推荐答案

在打开错误上游后找到了问题的根本原因并编写了补丁.这个补丁不会进入python 2.x系列.

After opening the bug upstream the root cause of the problem was found and a patch was written. This patch won't be going into the python 2.x series.

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