File.open 忽略路径 [英] File.open ignoring path

问题描述

我正在尝试将文件写入特定位置.当我使用 File.read("path/to/file") 时，它会打开正确的位置，但是当我使用以下内容时，它似乎忽略了路径.

I'm trying to write a file to a specific location. When I use File.read("path/to/file") it opens the correct location but when I use the following, it seems to disregard the path.

file_name = timestamp_filename("leads.csv")
dirname = File.dirname("C:/Users/Jordan/Dropbox/list/")

CSV.open(File.join(dirname, file_name), "w") do |csv|
    csv << ["array", "array1"]
end

我从计划任务运行它，它不可避免地最终将其保存到 C:\Users\Jordan\AppData\Local\Application Data\Application Data\Application Data\Application Data\Application Data\VirtualStore\Windows\SysWOW64.似乎计划任务从 C:\Windows\system32 运行它们的任务.

I'm running this from a scheduled task and it inevitably ends up saving it to C:\Users\Jordan\AppData\Local\Application Data\Application Data\Application Data\Application Data\Application Data\VirtualStore\Windows\SysWOW64. It also appears that scheduled tasks run their tasks from C:\Windows\system32.

我如何确保这会保存到所需的路径?

How do I make sure this saves to the path desired?

推荐答案

在 Windows 中，路径分隔符是反斜杠而不是正斜杠.在某些情况下，Windows 会默默地将正斜杠转换为反斜杠，但在某些情况下，正斜杠不起作用.

In Windows, the path separator is a backslash rather than a forward slash. Under some circumstances, Windows will silently convert forward slashes to backslashes, but there are cases where forward slashes won't work.

显然，这是其中之一！

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