该进程无法访问该文件，因为它正被另一个进程使用.c# [英] The process cannot access the file because it is being used by another process.c#

问题描述

我正在尝试使用 File.Copy() 函数将一张图像从一个位置复制到另一个位置，但它导致进程无法访问异常，任何人都可以帮助解决下面的代码块.我附上了截图例外.

I am trying to copy one image from one location to another location using File.Copy() function but it gives the process can not access exception,any one can please help on this bellow is the code block.I have attached screenshot for exception.

private void btnUpload_Click(object sender, EventArgs e)
{  
    string SourcePath;
    string RootDrive;
    string DestPath;
    string fileName;
    fileName = "";
        try
        {
            OpenFileDialog ofd = new OpenFileDialog();
            ofd.Title = "Select Image to Upload";
            ofd.Filter = "Jpg|*.jpg|Jpge|*.jpge|Gif|*.gif";
            ofd.FileName = null;
            if (ofd.ShowDialog() != DialogResult.Cancel)
            {
                fileName = ofd.FileName;

            }
            ofd.Dispose();
            DestPath = Directory.GetCurrentDirectory() + @"\Uploads\PropertyImages\";
                string destFile = System.IO.Path.Combine(DestPath, fileName);

                if (!System.IO.Directory.Exists(DestPath))
                {
                    System.IO.Directory.CreateDirectory(DestPath);
                }
                System.IO.File.Copy(fileName, destFile, true);                                   

        }
        catch (Exception ae)
        {
            MessageBox.Show(ae.Message, "Upload Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
        }

推荐答案

这可能是因为您试图将文件复制到自身.对 Combine() 的调用，正如您所拥有的，只是返回 fileName.更改以下行:

It's probably because you are attempting to copy the file to itself. The call to Combine(), as you have it, is just returning fileName. Change the following line:

string destFile = System.IO.Path.Combine(DestPath, fileName);

到

string destFile = System.IO.Path.Combine(DestPath, System.IO.Path.GetFileName(fileName));

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