如果 url 包含以下内容，则不要显示此内容 [英] Don't show this if the url contains the following

问题描述

我有一个简单的 div，如果访问者加载了某个 URL，我不想加载它.

I have a simple div which I don't want to load if the visitor loads up a certain URL.

看起来像这样:

<?php
if( stristr($_SERVER['PHP_SELF'], 'blog') == FALSE  )
{

echo "<div id="stuff"></div>";

}
?>

问题是...它不起作用...当我加载 www.url.com/blog 时，div#stuff 仍然显示.

Problem is... it doesn't work... when I load up www.url.com/blog the div#stuff still shows.

我只是睡眠不足还是上述方法应该有效?如果 url 包含 blog，如果没有 div 显示，你会怎么做?

Am I just lacking sleep or should the above work? What would you do to not have a div display if the url contains blog ?

推荐答案

尝试 $_SERVER['REQUEST_URI'] 代替:

Try $_SERVER['REQUEST_URI'] instead:

if (substr($_SERVER['REQUEST_URI'], 0, 5) !== '/blog') {
    echo '<div id="stuff"></div>';
}

REQUEST_URI 包含请求的 URI 路径和查询，而不仅仅是像 PHP_SELF 那样当前正在执行的脚本的文件名.

REQUEST_URI contains the requested URI path and query and not just the filename of the currently executing script like PHP_SELF does.

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