根据字符宽度将字符串分成多行(python) [英] Breaking string into multiple lines according to character width (python)

问题描述

我正在通过 PIL 在基本图像上绘制文本.一个要求是如果所有字符的组合宽度超过基本图像的宽度，它就会溢出到下一行.

I am drawing text atop a base image via PIL. One of the requirements is for it to overflow to the next line(s) if the combined width of all characters exceeds the width of the base image.

目前我正在使用 textwrap.wrap(text, width=16) 来实现这一点.这里 width 定义了一行中容纳的字符数.现在文本可以是任何内容，因为它是用户生成的.所以问题是硬编码 width 不会考虑 width 由于字体类型、字体大小和字符选择而产生的可变性.

Currently I'm using textwrap.wrap(text, width=16) to accomplish this. Here width defines the number of characters to accommodate in one line. Now the text can be anything since it's user generated. So the problem is that hard-coding width won't take into account width variability due to font type, font size and character selection.

我是什么意思?

好吧，想象一下我正在使用 DejaVuSans.ttf，大小为 14.W 的长度为 14，而i"的长度为 4.对于基本图像宽度为 400，单行最多可容纳 100 个 i 字符.但只有 29 个 W 字符.我需要制定一种更智能的换行方式，当字符宽度的总和超过基本图像宽度时，字符串会断开.

Well imagine I'm using DejaVuSans.ttf, size 14. A W is 14 in length, whereas an 'i' is 4. For a base image of width 400, up to 100 i characters can be accommodated in a single line. But only 29 W characters. I need to formulate a smarter way of wrapping to the next line, one where the string is broken when the sum of character-widths exceeds the base image width.

有人可以帮我制定这个吗?一个说明性的例子会很棒！

Can someone help me formulate this? An illustrative example would be great!

推荐答案

既然你知道每个字符的宽度，你应该把它做成一个字典，从中得到宽度来计算字符串宽度:

Since you know the width of each character, you should make that into a dictionary, from which you get the widths to calculate the stringwidth:

char_widths = {
    'a': 9,
    'b': 11,
    'c': 13,
    # ...and so on
}

从这里您可以查找每个字母并使用该总和来检查您的宽度:

From here you can lookup each letter and use that sum to check your width:

current_width = sum([char_widths[letter] for letter in word])

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