我如何将这种简单类型的 xsd 转换为复杂类型的 XSD [英] How do i convert this simple type xsd to a complex type XSD

问题描述

`我有一个简单类型的 xsd 元素，我想将其转换为复杂类型，因为我希望最终的 wsdl 是文档类型文字格式.你们能帮忙吗?

`I have a simple type xsd element which i want to convert to a complex type because i want the final wsdl to be document type literal format. Could you guys help?

<xsd:element name="Service">
    <xsd:simpleType>
      <xsd:restriction base="xsd:string">
        <xsd:enumeration value="loan.CreateLead" />
      </xsd:restriction>
    </xsd:simpleType>
  </xsd:element>

我希望将其转换为具有相同名称元素并具有枚举值的复杂类型.请让我知道这一点?谢谢补颜

I want this to be converted to a complex type with the same name element and having an enumeration value. Please let me know on this? Thanks Buyan

推荐答案

这是一种方法.问题是，您一次只能扩展/限制一个，因此采用两步法.

This is one way of doing it. The thing is, you can only extend/restrict one at a time, hence the two-steps approach.

我保持原来的不变仅供参考，否则第一个服务元素可能是限制"类型.

I kept the original one unchanged for reference only, otherwise the first Service element could've been of "arestriction" type.

<?xml version="1.0" encoding="utf-8" ?>
<!-- XML Schema generated by QTAssistant/XSD Module (http://www.paschidev.com) -->
<xsd:schema targetNamespace="http://tempuri.org/XMLSchema.xsd" xmlns="http://tempuri.org/XMLSchema.xsd" elementFormDefault="qualified" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <xsd:element name="Service">
        <xsd:simpleType>
            <xsd:restriction base="xsd:string">
                <xsd:enumeration value="loan.CreateLead"/>
            </xsd:restriction>
        </xsd:simpleType>
    </xsd:element>

    <xsd:simpleType name="arestriction">
        <xsd:restriction base="xsd:string">
            <xsd:enumeration value="loan.CreateLead"/>
        </xsd:restriction>
    </xsd:simpleType>

    <xsd:element name="Service1">
        <xsd:complexType>
            <xsd:simpleContent>
                <xsd:extension base="arestriction"/>
            </xsd:simpleContent>
        </xsd:complexType>
    </xsd:element>
</xsd:schema>

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