wxPython 文件对话框错误:缺少“|";在通配符字符串中! [英] wxPython file dialog error: missing "|" in the wildcard string!
问题描述
我在 Windows7 上,使用 Python 2.6 和 wxPython 2.8.10.1.我试图让这个打开文件对话框工作,但遇到了一个奇怪的错误.这对我来说似乎是一个有效的通配符字符串,但是每当我选择一个文件并在文件对话框中单击确定"时,我都会得到这个:
I am on Windows7, using Python 2.6 and wxPython 2.8.10.1. I am trying to get this Open File dialog to work but am running into a weird error. This looks like a valid wildcard string to me, but whenever I choose a file and click 'Ok' on the File Dialog, I get this:
Traceback (most recent call last):
File "D:\Projects\python\wxTest.py", line 92, in OnOpen
self.__DoOpen()
File "D:\Projects\python\wxTest.py", line 101, in __DoOpen
if open_dlg.ShowModal() == wx.ID_OK:
File "C:\Python26\lib\site-packages\wx-2.8-msw-unicode\wx\_windows.py", line 711, in ShowModal
return _windows_.Dialog_ShowModal(*args, **kwargs)
wx._core.PyAssertionError: C++ assertion "wxAssertFailure" failed at
..\..\src\common\filefn.cpp(1746) in wxParseCommonDialogsFilter():
missing '|' in the wildcard string!
当对话框打开时,一切看起来都很好.有什么想法吗?
When the dialog is open everything looks fine. Any ideas?
输入太快,忘记包含有问题的通配符字符串!对不起...
typing too fast, forgot to include the wildcard string in question! sorry...
wcd = "All files(*.*)|*.*|Text files (*.txt)|*.txt|"
open_dlg = wx.FileDialog(self, message='Choose a file', defaultDir=directory, defaultFile='', style=wx.OPEN | wx.CHANGE_DIR)
open_dlg.SetWildcard(wcd)
if open_dlg.ShowModal() == wx.ID_OK:
path = open_dlg.GetPath()
...
推荐答案
通配符字符串有一种古怪的格式,借鉴自 Win32:
The wildcard string has a quirky format, borrowed from Win32:
Desc1|wildcard1|Desc2|wildcard2 ...
应该有奇数个管道,以便管道分隔的部分形成对、描述和通配符.例如:
There should be an odd number of pipes, so that the pipe-separated pieces form pairs, a description, and a wildcard. For example:
Spreadsheet (*.xls)|*.xls|Plain-old text (*.txt)|*.txt|Random noise|*.dat
请注意,描述通常包含一个括号通配符,只是为了显示目的.
Note that the description often contains a parenthetical wildcard just for display purposes.
您的问题是尾随管道符号.删除它.
Your problem is the trailing pipe symbol. Remove it.
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