如何使用 GCDWebServerRequest 读取 POST 请求的正文 [英] How to read body of a POST request with GCDWebServerRequest
问题描述
我有以下处理程序来响应 POST 请求:
I have the following handler to respond to POST request:
[_webServer addHandlerForMethod:@"POST"
path:@"/"
requestClass:[GCDWebServerURLEncodedFormRequest class]
processBlock:^GCDWebServerResponse *(GCDWebServerRequest* request) {
NSString* value = [[(GCDWebServerURLEncodedFormRequest*)request arguments] objectForKey:@"value"];
NSString* html = [NSString stringWithFormat:@"<html><body><p>%@</p></body></html>", value];
return [GCDWebServerDataResponse responseWithHTML:html];
}];
当处理程序被触发时，NSString* value 一直给我空值.我能够调试和查看 GCDWebServerRequest 对象(屏幕截图).
When the handler is triggered, NSString* value keeps giving me null. I am able to debug and view the GCDWebServerRequest object (screenshot).
有一个字段 _data 我希望获得.
There is a field _data which I wish to obtain.
我可以知道如何去做吗?
May I know how to go about it?
这是我的 POST 请求以供参考:
Here is my POST request for reference:
var request = require('request');
request({
url: 'http://XX.XX.XX.XX:8080',
method: 'POST',
headers:{
'Content-Type': 'application/x-www-form-urlencoded',
},
body: "12345678"
}, function(error, response, body){
console.log(body);
});
我正在使用 npm request 来运行 POST 请求.如果我为我的 POST 请求做了 value=test，它会给我这个错误:
I am using npm request to run the POST request. If I did value=test for my POST request, it gives me this error:
推荐答案
对于 NPM request，如果你想使用 x-www-form-urlencoded，您将不得不调用参数 form 而不是 body.
For NPM request, if you wish to use content-type of x-www-form-urlencoded, you will have to call the parameter form instead of body.
示例:
request.post('http://service.com/upload', {form:{key:'value'}})
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