从 Excel 文档中获取超链接 URL [英] Getting a hyperlink URL from an Excel document

问题描述

我正在使用 Excel 文件阅读="http://pypi.python.org/pypi/xlrd" rel="noreferrer">xlrd.在一个列中，我有一个公司名称，它的格式为超链接(意味着它后面有一个 URL).当我获得单元格值时，我只能获得公司名称.我怎样才能获得它背后的网址?

I am reading an Excel file using xlrd. In one column I have a company name which is formatted as a hyperlink (meaning there is a URL behind it). When I get the cell value I only get the company name. How can I also get the URL behind it?

以下是使用 xlrd 模块读取 Excel 文件的代码(假设文件已导入).

Below is the code for reading an Excel file using the xlrd module (assume files are imported).

mainData_book = xlrd.open_workbook("IEsummary.xls", formatting_info=True)
mainData_sheet = mainData_book.sheet_by_index(0) # Get the first sheet 0
start = 1
end = 101
for counter in range(start, end):
    rowValues = mainData_sheet.row_values(counter, start_colx=0, end_colx=8)
    company_name = rowValues[0] #how i can get link here also??

推荐答案

在 xlrd 0.7.2 或更新版本中，您可以使用 hyperlink_map:

In xlrd 0.7.2 or newer, you can use hyperlink_map:

import xlrd
mainData_book = xlrd.open_workbook("IEsummary.xls", formatting_info=True)
mainData_sheet = mainData_book.sheet_by_index(0)
for row in range(1, 101):
    rowValues = mainData_sheet.row_values(row, start_colx=0, end_colx=8)
    company_name = rowValues[0]

    link = mainData_sheet.hyperlink_map.get((row, 0))
    url = '(No URL)' if link is None else link.url_or_path
    print(company_name.ljust(20) + ': ' + url)

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