XPath 选择多个标签 [英] XPath to select multiple tags

问题描述

鉴于这种简化的数据格式:

Given this simplified data format:

<a>
    <b>
        <c>C1</c>
        <d>D1</d>
        <e>E1</e>
        <f>don't select this one</f>
    </b>
    <b>
        <c>C2</c>
        <d>D2</d>
        <e>E1</e>
        <g>don't select me</g>
    </b>
    <c>not this one</c>
    <d>nor this one</d>
    <e>definitely not this one</e>
</a>

您将如何选择作为 B 子代的所有 C、D 和 E元素?

How would you select all the Cs, Ds and Es that are children of B elements?

基本上，类似于:

a/b/(c|d|e)

在我自己的情况下，不仅仅是 a/b/，查询导致选择那些 C、D、E 节点实际上非常复杂，所以我想避免这样做:

In my own situation, instead of just a/b/, the query leading up to selecting those C, D, E nodes is actually quite complex so I'd like to avoid doing this:

a/b/c|a/b/d|a/b/e

这可能吗?

推荐答案

一个正确答案是:

/a/b/*[self::c or self::d or self::e]

请注意这一点

a/b/*[local-name()='c' or local-name()='d' or local-name()='e']

既太长又不正确.此 XPath 表达式将选择如下节点:

is both too-long and incorrect. This XPath expression will select nodes like:

OhMy:c

NotWanted:d 

QuiteDifferent:e

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