按属性名称选择 xml 节点，忽略该属性的命名空间 [英] Select xml node by attribute name ignoring namespace of that attribute

问题描述

我有一个这样的节点:

<meta name="og:description" content="Here's the content" />

如果名称是描述"，无论它是否在命名空间中，我都希望能够选择此元素.如果元标记的名称是og:description"、description"、blah:description"等，我需要能够选择它.

I want to be able to select this element if the name is "description" whether it's in a namespace or not. I need to be able to select the meta tag if it's name is "og:description", "description", "blah:description", etc.

我已经看到了 xpath 的资源，这些资源展示了如何在命名空间内进行选择，但并非不考虑命名空间.

I've seen resources for xpath that show how to select within a namespace, but not irrespective of a namespace.

推荐答案

使用 XPath 2 你可以:

Using XPath 2 you could do:

 /meta[ends-with(@name, 'description')]

对于 XPath 1，我们需要:

For XPath 1 we need:

 /meta['description' = substring(@name, string-length(@name) - string-length('description') + 1)]

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