需要帮助嵌套兄弟姐妹 [英] Need help nesting siblings

查看:31
本文介绍了需要帮助嵌套兄弟姐妹的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想做一个能够根据属性值(outline-level)嵌套一组同级元素的转换.

I want to make a transformation that is able to nest a set of sibling elements depending on value of attribute (outline-level).

这是输入的xml文件:

This is the input xml file:

<text>
    <para style="Heading 1" outline-level="1">Level 1</para>
    <para xml:lang="en" style="Directive">Concept: 1</para>
    <para xml:lang="en" style="Heading 2" outline-level="2">Level 2</para>
    <para xml:lang="en" style="Directive">Concept: 2</para>
    <para xml:lang="en" style="Heading 2" outline-level="2">Level 2</para>
    <para xml:lang="en" style="Directive">Concept: 3</para>
    <para xml:lang="en" style="Heading 3" outline-level="3">Level 3</para>
    <para xml:lang="en" style="Directive">Concept: 4</para>
    <para xml:lang="en" style="Heading 3" outline-level="3">Level 3</para>
    <para xml:lang="en" style="Directive">Concept: 5</para>
    <para xml:lang="en" style="Heading 1" outline-level="1">Level 1</para>
    <para xml:lang="en" style="Directive">Concept: 6</para>
    <para xml:lang="en" style="Heading 2" outline-level="2">Level 2</para>
    <para xml:lang="en" style="Directive">Concept: 7</para>
    <para xml:lang="en" style="Heading 3" outline-level="3">Level 3</para>
    <para xml:lang="en" style="Directive">Concept: 8</para>
</text>

这就是我想要实现的:

<root>
    <para id="Concept: 1">Level 1
        <para id="Concept: 2">Level 2</para>
        <para id="Concept: 3">Level 2
            <para id="Concept: 4">Level 3</para>
            <para id="Concept: 5">Level 3</para>
        </para>
    </para>
    <para id="Concept: 6">Level1
        <para id="Concept: 7">Level 2
            <para id="Concept: 8"/>
        </para>
    </para>
</root>

嵌套级别必须由 @outline-level 的值决定.数字越大,元素嵌套越深.

The nesting level have to be determined by the value of @outline-level. The bigger is that number the deeper is the element nested.

任何想法将不胜感激.

推荐答案

试试这个方法?

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:key name="child-paras" match="para" use="generate-id(preceding-sibling::para[@outline-level = current()/@outline-level - 1][1])" />

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="/text">
    <root>
        <xsl:apply-templates select="para[@outline-level=1]"/>
    </root>
</xsl:template>

<xsl:template match="para">
    <para id="{following-sibling::para[1]}">
        <xsl:value-of select="." />
        <xsl:apply-templates select="key('child-paras', generate-id())"/>
    </para>
</xsl:template>

</xsl:stylesheet>

当应用于您的示例输入时,结果将是:

When applied to your example input, the result will be:

<?xml version="1.0" encoding="UTF-8"?>
<root>
   <para id="Concept: 1">Level 1<para id="Concept: 2">Level 2</para>
      <para id="Concept: 3">Level 2<para id="Concept: 4">Level 3</para>
         <para id="Concept: 5">Level 3</para>
      </para>
   </para>
   <para id="Concept: 6">Level 1<para id="Concept: 7">Level 2<para id="Concept: 8">Level 3</para>
      </para>
   </para>
</root>

其中(除了缩进差异)与您预期的输出相同 - 除了最后一个 para 其中 id="Concept: 8" 包含文本节点 Level 3" - 我认为这是正确的.

which (other than differences in indenting) is identical to your expected output - except that the last para where id="Concept: 8" contains the text node "Level 3" - which I believe is correct.

这篇关于需要帮助嵌套兄弟姐妹的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆