xml:如何在 .xml 文件中引用 .xsd 文件? [英] xml : how to reference a .xsd file at .xml file?

问题描述

我想在浏览器中查看 .xsd 文件中定义的 xml 文件.请帮我检查以下两个文件，并指出我需要做什么.这两个文件在同一个文件夹下.

I want to see xml file in browser as I define in .xsd file. Please check the following two files for me and point out what do I need to do. These two files are under same folder.

员工.xml

 <?xml version="1.0"?>

<employee xmlns="http://www.w3schools.com" 
          xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
          xsi:schemaLocation="employee.xsd">

  <firstname>John</firstname>
  <lastname>Smith</lastname>
</employee>

员工.xsd

<xs:element name="employee">
  <xs:complexType>
    <xs:sequence>
      <xs:element name="firstname" type="xs:string" fixed="red" />
      <xs:element name="lastname" type="xs:string"/>
    </xs:sequence>
  </xs:complexType>
</xs:element>

推荐答案

您犯了两个错误:一个在架构文件中，另一个在架构文件的 xsi:schemaLocation 属性值的语法中XML 文件.

You made two errors: one in the schema file and another in the syntax of the value of the xsi:schemaLocation attribute of the XML file.

主要错误是您的employee.xsd 文件只是XML Schema 的一个片段.您应该完成对employee.xsd 的包含.例如，

The main error is that your employee.xsd file is only a fragment of the XML Schema. You should complete the contain of the employee.xsd. For example,

<?xml version="1.0" encoding="utf-8"?>
<xs:schema targetNamespace="http://www.w3schools.com/RedsDevils"
    elementFormDefault="qualified"
    xmlns="http://www.w3schools.com/RedsDevils employee.xsd"
    xmlns:xs="http://www.w3.org/2001/XMLSchema">

    <xs:element name="employee">
        <xs:complexType>
            <xs:sequence>
                <xs:element name="firstname" type="xs:string" fixed="red" />
                <xs:element name="lastname" type="xs:string"/>
            </xs:sequence>
        </xs:complexType>
    </xs:element>
</xs:schema>

和employee.xml:

and employee.xml:

<?xml version="1.0" encoding="utf-8"?>
<employee xmlns="http://www.w3schools.com/RedsDevils"
          xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
          xsi:schemaLocation="http://www.w3schools.com/RedsDevils employee.xsd">

    <firstname>John</firstname>
    <lastname>Smith</lastname>
</employee>

因为您在 XML 文件中定义了默认命名空间，架构位置属性 xsi:schemaLocation 必须由命名空间和以空格分隔的架构路径组成.我更改了命名空间名称，使其更加独特:"http://www.w3schools.com/RedsDevils" 而不是 "http://www.w3schools.com".

Because you define default namespace in the XML file, the schema location attribule xsi:schemaLocation must consist from the the namespace and the path to the schema devided with the blank. I changed the namespace name so that it will be a little more unique: "http://www.w3schools.com/RedsDevils" instead of "http://www.w3schools.com".

最后我可以补充一点，XML 文件employee.xml 与架构employee.xsd 不对应，因为元素John 的值other 为red，但可能正是您想要测试的.

At the end I can add that the XML file employee.xml not corresponds to the schema employee.xsd because the element <firstname>John</firstname> has the value other as red, but probably exactly this you wanted to test.

这篇关于xml:如何在 .xml 文件中引用 .xsd 文件?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！