如何在 XSLT 中获得以下兄弟 [英] How to get the following sibling in XSLT

问题描述

我对 XSLT 还很陌生，这是我的 XML:

I am fairly new to XSLT and this is my XML:

<projects>
    <project>
        <number>1</number>
        <title>Project X</title>
    </project>
    <project>
        <number>2</number>
        <title>Project Y</title>
    </project>
    <project>
        <number>3</number>
        <title>Project Z</title>
    </project>
</projects>

如果我有一个项目并且想要得到它后面的兄弟，我该怎么做?

If I have one project and want to get the sibling that follows it, how can I do that?

这段代码似乎对我不起作用:

This code doesn't seem to work for me:

/projects[title="Project X"]/following-sibling

推荐答案

这实际上是一个完全 XPath 的问题.

This is actually a completely XPath question.

使用:

/*/project[title = 'Project X']/following-sibling::project[1]

这将选择作为 XML 文档中顶部元素的子元素的任何 Project 元素的任何第一个以下同级 Project 和至少以下元素的字符串值它的 title 子元素是字符串 "Project X".

This selects any first following sibling Project of any Project element that is a child of the top element in the XML document and the string value of at least of one of its title children is the string "Project X".

基于 XSLT 的验证:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="/">
     <xsl:copy-of select=
      "/*/project[title = 'Project X']/following-sibling::project[1]"/>
 </xsl:template>
</xsl:stylesheet>

当此转换应用于提供的 XML 文档时:

<projects>
    <project>
        <number>1</number>
        <title>Project X</title>
    </project>
    <project>
        <number>2</number>
        <title>Project Y</title>
    </project>
    <project>
        <number>3</number>
        <title>Project Z</title>
    </project>
</projects>

计算 XPath 表达式并将正确选择的元素复制到输出:

<project>
   <number>2</number>
   <title>Project Y</title>
</project>

这篇关于如何在 XSLT 中获得以下兄弟的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！