如何使用xslt修改xml文件 [英] how to modify xml file using xslt
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问题描述
我需要通过 xsl 文件更改 xml 中某个节点的特定元素的值 下面是我的 xml 数据
I need to change the value of particular element of a node in a xml through xsl file Below is my xml data
<hospitals>
<hospital>
<department>
<clinic>
<cid>8</cid>
<clinicName>clinic8</clinicName>
<status>1</status>
</clinic>
<clinic>
<cid>9</cid>
<clinicName>clinic9</clinicName>
<status>0</status>
</clinic>
<depId>3</depId>
<departmentName>dental</departmentName>
</department>
<hospId>2</hospId>
<hospitalName>appolo</hospitalName>
</hospital>
<hospital>
<department>
<clinic>
<cid>82</cid>
<clinicName>clinic82</clinicName>
<status>0</status>
</clinic>
<clinic>
<cid>92</cid>
<clinicName>clinic92</clinicName>
<status>0</status>
</clinic>
<depId>4</depId>
<departmentName>mental</departmentName>
</department>
<hospId>2</hospId>
<hospitalName>manipal</hospitalName>
</hospital>
</hospitals>
例如,我需要根据 id 选择诊所 9,即 9 并将状态 0 更改为 1
for example, I need to select clinic9 based on its id ie 9 and change the status 0 to 1
我是这样试的
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="hospId"/>
<xsl:param name="depId" />
<xsl:param name="clinicId"/>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="hospitals/hospital[hospId='2']/department[depId='3']/clinic[cid='9']">
<xsl:choose>
<xsl:when test="cid ='9'">
<xsl:element name="status">123</xsl:element>
</xsl:when>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
但值没有改变...
推荐答案
如果您尝试修改/替换特定元素,则需要匹配该元素.例如,如果您要替换特定的 status
元素,则需要匹配该特定元素.
If you are trying to modify/replace a specific element, you need to match that element. For example, if you are trying to replace a specific status
element, you need to match that specific element.
修改后的 XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="hospId" select="'2'"/>
<xsl:param name="depId" select="'3'"/>
<xsl:param name="clinicId" select="'9'"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="hospitals/hospital[hospId='2']/department[depId='3']/clinic[cid='9']/status">
<status>123</status>
</xsl:template>
</xsl:stylesheet>
XML 输出
<hospitals>
<hospital>
<department>
<clinic>
<cid>8</cid>
<clinicName>clinic8</clinicName>
<status>1</status>
</clinic>
<clinic>
<cid>9</cid>
<clinicName>clinic9</clinicName>
<status>123</status>
</clinic>
<depId>3</depId>
<departmentName>dental</departmentName>
</department>
<hospId>2</hospId>
<hospitalName>appolo</hospitalName>
</hospital>
<hospital>
<department>
<clinic>
<cid>82</cid>
<clinicName>clinic82</clinicName>
<status>0</status>
</clinic>
<clinic>
<cid>92</cid>
<clinicName>clinic92</clinicName>
<status>0</status>
</clinic>
<depId>4</depId>
<departmentName>mental</departmentName>
</department>
<hospId>2</hospId>
<hospitalName>manipal</hospitalName>
</hospital>
</hospitals>
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