XSLT 中的身份转换 [英] Identity transformation in XSLT
问题描述
我有这个源 XML:
<?xml version="1.0"?>
<root>
<item1>
<name>test</name>
<price>160</price>
<stock>4</stock>
<country>Belgium</country>
</item1>
<item2>
<name>Alfa</name>
<price>140</price>
<stock>3</stock>
<country>Turkey</country>
</item2>
<item3>
<name>Beta</name>
<price>110</price>
<stock>48</stock>
<country>Holland</country>
</item3>
<product id="p1">
<name>Delta</name>
<price>800</price>
<stock>4</stock>
<country>Denmark</country>
</product>
<product id="p2">
<name>Golf</name>
<price>1000</price>
<stock>5</stock>
<country>Germany</country>
</product>
<product id="p3">
<name>Alfa</name>
<price>1200</price>
<stock>19</stock>
<country>Germany</country>
</product>
<product id="p4">
<name>Foxtrot</name>
<price>1500</price>
<stock>5</stock>
<country>Australia</country>
</product>
<product id="p5">
<name>Tango</name>
<price>1225</price>
<stock>3</stock>
<country>Japan</country>
</product>
</root>
我希望它看起来像这样:
<?xml version="1.0"?>
<root>
<action>
<name>test</name>
<price>160</price>
<stock>4</stock>
<country>Belgium</country>
</action>
<action>
<name>Alfa</name>
<price>140</price>
<stock>3</stock>
<country>Turkey</country>
</action>
<action>
<name>Beta</name>
<price>110</price>
<stock>48</stock>
<country>Holland</country>
</action>
<action>
<name>Delta</name>
<price>800</price>
<stock>4</stock>
<country>Denmark</country>
</action>
<action>
<name>Golf</name>
<price>1000</price>
<stock>5</stock>
<country>Germany</country>
</action>
<action>
<name>Alfa</name>
<price>1200</price>
<stock>19</stock>
<country>Germany</country>
</action>
<action>
<name>Foxtrot</name>
<price>1500</price>
<stock>5</stock>
<country>Australia</country>
</action>
<action>
<name>Tango</name>
<price>1225</price>
<stock>3</stock>
<country>Japan</country>
</action>
</root>
所以
<action>
而
And the <product> loses its attribute, and also turns into
<action>
有人可以告诉我如何用 XSLT 做到这一点吗?因为我现在有 2 个不同的 XSL.我想将它们组合起来以创建一个 XSL.
Can somebody show me how to do this with XSLT? Because I have 2 different XSL's now. And I want to combine them to create just one XSL.
提前致谢
推荐答案
这种转变:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="product|*[starts-with(name(), 'item')]">
<action>
<xsl:apply-templates select="node()|@*"/>
</action>
</xsl:template>
<xsl:template match="product/@id"/>
</xsl:stylesheet>
应用于提供的 XML 文档时:
<root>
<item1>
<name>test</name>
<price>160</price>
<stock>4</stock>
<country>Belgium</country>
</item1>
<item2>
<name>Alfa</name>
<price>140</price>
<stock>3</stock>
<country>Turkey</country>
</item2>
<item3>
<name>Beta</name>
<price>110</price>
<stock>48</stock>
<country>Holland</country>
</item3>
<product id="p1">
<name>Delta</name>
<price>800</price>
<stock>4</stock>
<country>Denmark</country>
</product>
<product id="p2">
<name>Golf</name>
<price>1000</price>
<stock>5</stock>
<country>Germany</country>
</product>
<product id="p3">
<name>Alfa</name>
<price>1200</price>
<stock>19</stock>
<country>Germany</country>
</product>
<product id="p4">
<name>Foxtrot</name>
<price>1500</price>
<stock>5</stock>
<country>Australia</country>
</product>
<product id="p5">
<name>Tango</name>
<price>1225</price>
<stock>3</stock>
<country>Japan</country>
</product>
</root>
产生想要的、正确的结果:
<root>
<action>
<name>test</name>
<price>160</price>
<stock>4</stock>
<country>Belgium</country>
</action>
<action>
<name>Alfa</name>
<price>140</price>
<stock>3</stock>
<country>Turkey</country>
</action>
<action>
<name>Beta</name>
<price>110</price>
<stock>48</stock>
<country>Holland</country>
</action>
<action>
<name>Delta</name>
<price>800</price>
<stock>4</stock>
<country>Denmark</country>
</action>
<action>
<name>Golf</name>
<price>1000</price>
<stock>5</stock>
<country>Germany</country>
</action>
<action>
<name>Alfa</name>
<price>1200</price>
<stock>19</stock>
<country>Germany</country>
</action>
<action>
<name>Foxtrot</name>
<price>1500</price>
<stock>5</stock>
<country>Australia</country>
</action>
<action>
<name>Tango</name>
<price>1225</price>
<stock>3</stock>
<country>Japan</country>
</action>
</root>
说明:
身份规则按原样"复制每个节点.
The identity rule copies every node "as-is".
我们有两个模板来覆盖身份规则.第一个模板匹配任何 product 或名称以字符串 item 开头的任何元素.它通过创建和输出 action 元素有效地将匹配的元素重命名"为 action.
We have two templates overriding the identity rule. The first template matches any product or any element whose name starts with the string item. It effectively "renames" the matched element to action by creating and outputting an action element.
第二个覆盖模板匹配任何 product 元素的任何 id 属性.该模板没有正文，可以有效地删除"匹配的属性——它不会在输出中复制/重新创建.
The second overriding template matches any id attribute of any product element. This template has no body, which effectively "deletes" the matched attribute -- it is not copied/recreated in the output.
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