根据其属性查找xml元素并更改其值 [英] find xml element based on its attribute and change its value
问题描述
我正在使用 python xmlElementTree 并希望根据其属性分配或修改 xml 元素值.有人可以告诉我怎么做吗?
I am using python xmlElementTree and want to assign or modify a xml element value based on its attribute. Can somebody give me an idea how to do this?
例如:这是一个xml文件,我需要根据属性sys/phoneNumber/1"、sys2/SMSnumber/1"等设置元素number"的值.
For example: Here is a xml file and I need to set the value for the element "number" based on the attribute "sys/phoneNumber/1", "sys2/SMSnumber/1" and so on.
<root>
<phoneNumbers>
<number topic="sys/phoneNumber/1" update="none" />
<number topic="sys/phoneNumber/2" update="none" />
<number topic="sys/phoneNumber/3" update="none" />
</phoneNumbers>
<gfenSMSnumbers>
<number topic="sys2/SMSnumber/1" update="none" />
<number topic="sys2/SMSnumber/2" update="none" />
</gfenSMSnumbers>
</root>
为 XML 文件中的标签根添加了闭包.
edit: Added closure for the tag root in the XML file.
推荐答案
您可以这样访问属性值:
You can access the attribute value as this:
from elementtree.ElementTree import XML, SubElement, Element, tostring
text = """
<root>
<phoneNumbers>
<number topic="sys/phoneNumber/1" update="none" />
<number topic="sys/phoneNumber/2" update="none" />
<number topic="sys/phoneNumber/3" update="none" />
</phoneNumbers>
<gfenSMSnumbers>
<number topic="sys2/SMSnumber/1" update="none" />
<number topic="sys2/SMSnumber/2" update="none" />
</gfenSMSnumbers>
</root>
"""
elem = XML(text)
for node in elem.find('phoneNumbers'):
print node.attrib['topic']
# Create sub elements
if node.attrib['topic']=="sys/phoneNumber/1":
tag = SubElement(node,'TagName')
tag.attrib['attr'] = 'AttribValue'
print tostring(elem)
忘了说,如果你的ElementTree版本大于1.3,可以使用XPath:
forget to say, if your ElementTree version is greater than 1.3, you can use XPath:
elem.find('.//number[@topic="sys/phoneNumber/1"]')
http://effbot.org/zone/element-xpath.htm
或者你可以使用这个简单的:
or you can use this simple one:
for node in elem.findall('.//number'):
if node.attrib['topic']=="sys/phoneNumber/1":
tag = SubElement(node,'TagName')
tag.attrib['attr'] = 'AttribValue'
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