如何在 for-each xslt 语句中选择父节点的每个子节点? [英] How to select each child node of a parent in a for-each xslt statement?

问题描述

我想从每个循环中的adviceRow 元素(参见下面的xml 数据)中选择所有子节点.

I want to select all child nodes from the adviceRow element (see xml data hereunder) in a for each loop.

我想避免编写这样的 xslt 文件:

I want to avoid having to write an xslt file like this:

<xsl:for-each select="Tables/routeAdviceTable/routeAdviceRows/adviceRow">
   <xsl:value-of select="cog" />
   <xsl:value-of select="current" />
   <xsl:value-of select="distance" />
   <xsl:value-of select="dtg" />
   etc..
</xsl:for-each>

因为一行可以有很多单元格(我有很多相似但内容不同的表格)

Because a row can have many cells (and i have lots of similar but contentwise different tables)

我可以使用嵌套的 for-each 循环吗?类似的东西:

Can I work with a nested for-each loop? Something like:

for-each advice row:
    for-each child of advicerow?

<Tables>
<routeAdviceTable>
    <routeAdviceRows>
        <adviceRow>
            <cog>313</cog>
            <current>0.3</current>
            <distance>58.8</distance>
            <dtg>1374786000000</dtg>
            <latitude>????</latitude>
            <longitude>????</longitude>
            <pressure>22.300001</pressure>
            <sea>0.2</sea>
            <sog>14.7</sog>
            <stw>???</stw>
            <swell>1.7</swell>
            <waves>1.711724324567694</waves>
            <wind>0.8</wind>
        </adviceRow>
    </routeAdviceRows>
</routeAdviceTable>

谢谢

推荐答案

是的，您可以嵌套 for-each 循环.

Yes, you can nest for-each loops.

试试这个

<xsl:for-each select="Tables/routeAdviceTable/routeAdviceRows/adviceRow">
  <xsl:for-each select="./*">
    <!-- 
      Your code i.e.
      <td class="{name(.)}">
        <xsl:value-of select="."></xsl:value-of>
      </td>
    -->
  </xsl:for-each>
</xsl:for-each>

xpath."指的是当前节点(又名上下文节点")，/*"选择上下文节点的所有子节点.

The xpath "." refers to the current node (a.k.a the "context node"), "/*" select all the child nodes of the context node.

这篇关于如何在 for-each xslt 语句中选择父节点的每个子节点?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！