XSLT 删除空节点和带有 -1 的节点 [英] XSLT To remove empty nodes and nodes with -1
问题描述
我不是 XSLT 向导.
I'm not an XSLT wizard.
我有当前用于删除空节点的 XSLT:
I have the current XSLT i'm using to remove empty nodes:
string strippingStylesheet = "<xsl:stylesheet version=\"1.0\" xmlns:xsl=\"http://www.w3.org/1999/XSL/Transform\">" +
"<xsl:template match=\"@*|node()\">" +
"<xsl:if test=\". != ''\">" +
"<xsl:copy>" +
"<xsl:apply-templates select=\"@*|node()\"/>" +
"</xsl:copy>" +
"</xsl:if></xsl:template></xsl:stylesheet>";
我需要找到一种方法来删除其中包含 -1 的节点.以前的开发人员认为将系统中的每个 int 都默认为 -1 是个好主意,是的,这意味着所有 DB 字段都包含 -1 而不是 null.
I need to find a way to also remove nodes with -1 in them. A previous developer thought it would be a good idea to make every int in the system be defaulted to -1, and yes that means all DB fields have -1 in them instead of null.
尽管我想打败死马(用棍子、蝙蝠、火箭筒),但我需要重新开始工作并完成这项工作.
So as much as I want to beat the dead horse (with a stick, bat, bazooka), I need to get back to work and get this done.
任何帮助都会很棒.
推荐答案
我有我正在使用的当前 XSLT删除空节点:
I have the current XSLT i'm using to remove empty nodes:
.........
我需要找到一种方法来删除其中包含 -1 的节点
I need to find a way to also remove nodes with -1 in them
我猜需要删除所有空节点".
I guess that it is required to remove all "empty nodes".
处理取决于空节点"的定义.在您的情况下,一个合理的定义是:任何没有属性和子元素的元素,或者没有属性并且只有一个子元素是值为 -1
的文本节点.
The processing depends on the definition of "empty node". One reasonable definition in your case is: Any element that doesn't have attributes and children or doesn't have attributes and has only one child that is a text node with value -1
.
对于这个定义,这里有一个简单的解决方案.
For this definition here is a simple solution.
这种转变:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(@*) and not(*) and (not(text()) or .=-1)]"/>
</xsl:stylesheet>
应用于此示例 XML 文档时:
<t>
<a>-1</a>
<a>2</a>
<b><c/></b>
<d>-1</d>
<d>15</d>
<e x="1"/>
<f>foo</f>
</t>
产生想要的、正确的结果:
<t>
<a>2</a>
<b/>
<d>15</d>
<e x="1"/>
<f>foo</f>
</t>
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