如何在一个文档中解析多个连续的 xml 文件? [英] How to parse multiple, consecutive xml files in one document?
问题描述
我有一个大文本文件,它是一系列 XML 有效文档,看起来像这样:
I have a big text file that is a sequence of XML-valid documents that looks something like this:
<DOC>
<TEXT> ... </TEXT>
...
</DOC>
<DOC>
<TEXT> ... </TEXT>
...
</DOC>
等等.没有 ,
分隔每个单独的 xml.在 Java 中解析它并获取每个
中
下的值的最佳方法是什么?
etc. There is no <?xml version="1.0">
, the <DOC></DOC>
delimits each separate xml. What's the best way to parse this in Java and get the values under <TEXT>
in each <DOC>
?
如果我将整个内容传递给 DocumentBuilder,我会收到错误消息,指出文档格式不正确.有没有比简单地遍历更好的解决方案,为每个
构建一个字符串?
If I pass the whole thing to a DocumentBuilder, I get an error saying the document is not well formed. Is there a better solution than simply traversing through, a building a string for each <DOC>
?
推荐答案
valid XML 文档必须有一个 root 元素,您可以在该元素下指定所有其他元素.此外,在一个文档中只能存在一个 root 元素.看看 XML 规范(见第 2 点)
A valid XML document must have a root element under which you can specify all other elements. Also, in a document only ONE root element can be present. have a look on XML Specification (see point 2)
因此,为了解决您的问题,您可以将文本文件的所有内容放入一个字符串(或 StringBuffer/StringBuilder...)中,并将该字符串放在 <root>
和 标签例如,
So, to overcome your issue, you can take all the content of your text file into a String (or StringBuffer/StringBuilder...) And put this string in between <root>
and </root>
tags
e.g ,
String origXML = readContentFromTextFile(fileName);
String validXML = "<root>" + origXML + "</root>";
//parse validXML
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