XML 架构:用相应的架构替换导入 [英] XML Schema: replacing imports with corresponding schema

问题描述

我有一个 XML 架构，其中包含多个导入，而这些导入又包含导入.我需要生成语义相等的模式，其中所有导入都是内联的.我想替换这些:

I have a XML Schema that contains multiple imports which in turn contain imports. I need to generate semantically equal schema where all imports are inlined. I want to replace these:

<xs:import namespace="http://some.name/" schemaLocation="./path/to/it.xsd"/>

带有引用模式的内容.而且我需要将输出作为字符串，而不是某些内部表示.

with the contents of referenced schemata. And I need to get output as a string, not as some internal representation.

我尝试了 Apache Xerces，但没有找到将 XSModel 写入字符串的方法.有吗?

I tried Apache Xerces but did not find a way to write XSModel to a string. Is there?

我尝试了 Apache XmlSchema 2 但是当它写入 XML Schema 时它不会替换导入声明带架构.

I tried Apache XmlSchema 2 but when it writes XML Schema it does not replace import declarations with schema.

有什么图书馆可以做到吗?有什么建议吗?

Is there any library that can do it? Any suggestions?

谢谢.

推荐答案

xsd:include 通常可以被内联，但 xsd:import 不能.这是因为 xsd:import 用于引用不同目标命名空间的架构文档，并且您不能在同一个架构文档中拥有具有不同目标命名空间的组件.

xsd:include can usually be inlined, but xsd:import can't. That's because xsd:import is used to reference a schema document for a different target namespace, and you can't have components with different target namespaces in the same schema document.

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