使用 XStream 读取元素属性值 [英] Reading Element attribute value using XStream
问题描述
我无法查找元素的属性值.我的 XML 是
I am not able lookup attribute value of an element. My XML is
<Person>
<BirthDate>2008-01-04</BirthDate>
<FirstName>Affo</FirstName>
<Gender tc="200">Male</Gender>
<LastName></LastName>
<Occupation>false</Occupation>
<Age>4</Age>
</Person>
我对
感兴趣.我的 POJO 看起来像这样:
I am interested in <Gender tc="200">Male</Gender>
. My POJO looks like this:
private String FirstName;
private String LastName;
private String Occupation;
@XStreamAsAttribute
@XStreamAlias("tc")
private String genderTC;
private String Gender;
private String birthDate;
private int age;
来自 XML 是
XStream stream = new XStream(new DomDriver());
stream.processAnnotations(PersonType.class);
PersonType person = (PersonType) stream.fromXML(file);
System.out.println(person.getFirstName());
System.out.println(person.getGenderTC());
System.out.println(person.getGender());
这里对于 person.getGenderTC()
我得到空值.有趣的部分是当我颠倒过程并使用相同的 PersonType pojo 生成 xml 时,我得到了以下 XML:
Here for person.getGenderTC()
I am getting null. Interesting part is when I reversed the process and generated the xml using same PersonType pojo, I got following XML:
<Person tc="111">
<FirstName>Himanshu</FirstName>
<Gender>M</Gender>
<Age>28</Age>
</Person>
推荐答案
@BlaiseDoughan 太好了,感谢您的支持.你是否可以请告诉我如何将 EclipseLink MOXy 与我的项目集成不使用 jaxb.properties?要包含哪些库/JAR?在两者之间,我知道 EclipseLink JAXB (MOXy) 实现来获得属性.我唯一的预感是 jaxb.properties 文件.
@BlaiseDoughan That's great and I appreciate your support. Can you please tell me how can I integrate EclipseLink MOXy with my project without using jaxb.properties? What are the libraries/JARs to include? In between I am aware of EclipseLink JAXB (MOXy) implementation to get attribute. My only hunch is jaxb.properties file.
人
以下是您如何使用 MOXy 的 @XmlPath
注释来完成您正在寻找的映射:
Below is how you could use MOXy's @XmlPath
annotation to do the mapping you are looking for:
package forum11417620;
import javax.xml.bind.annotation.*;
import org.eclipse.persistence.oxm.annotations.XmlPath;
@XmlRootElement(name="Person")
@XmlAccessorType(XmlAccessType.FIELD)
public class Person {
@XmlElement(name="FirstName")
private String firstName;
@XmlElement(name="LastName")
private String lastName;
@XmlElement(name="Occupation")
private String occupation;
@XmlPath("Gender/@tc")
private String genderTC;
@XmlPath("Gender/text()")
private String gender;
@XmlElement(name="BirthDate")
private String birthDate;
@XmlElement(name="Age")
private int age;
}
演示
下面是一个示例,说明如何在没有 jaxb.properties
文件的情况下引导 MOXy JAXBContext
.
Below is an example of how you can bootstrap a MOXy JAXBContext
without a jaxb.properties
file.
package forum11417620;
import java.io.File;
import javax.xml.bind.*;
import org.eclipse.persistence.jaxb.JAXBContextFactory;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContextFactory.createContext(new Class[] {Person.class}, null);
Unmarshaller unmarshaller = jc.createUnmarshaller();
File xml = new File("src/forum11417620/input.xml");
Person person = (Person) unmarshaller.unmarshal(xml);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(person, System.out);
}
}
input.xml/输出
<?xml version="1.0" encoding="UTF-8"?>
<Person>
<FirstName>Affo</FirstName>
<LastName></LastName>
<Occupation>false</Occupation>
<Gender tc="200">Male</Gender>
<BirthDate>2008-01-04</BirthDate>
<Age>4</Age>
</Person>
必需的二进制文件(来自 http://www.eclipse.org/eclipselink/下载/)
选项 #1 - EclipseLink JAR(来自安装程序 Zip)
- eclipselink.jar
选项 #2 - MOXy 捆绑包(来自 OSGi Bundles Zip)
- org.eclipse.persistence.moxy.jar
- org.eclipse.persistence.core.jar
- org.eclipse.persistence.asm.jar
Maven
我在 Git Hub 上有示例 pom.xml
文件作为我博客中一些示例的一部分:
I have example pom.xml
files on Git Hub as part of some examples from my blog:
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