Java XML 解析 [英] Java XML parsing

问题描述

我需要像这样从 XML 文件中提取(使用 Java)给定名称标签的标签:

I need to extract (using Java) the tag for the given name tag from XML file like this:

这是我的 XML 文件:

Here is my XML file:

<aa>
  <bb>
    <name>k1</name>
    <value>5</value>
  </bb>
  <bb>
    <name>k2</name>
    <value>7</value>
 </bb>
</aa>

函数的输入:的完整路径标签，例如:/aa/bb/name=k2
(此示例的输出应返回 7)

还有更高级的问题:我需要从 XML 文件中提取所有名称:值对，然后名称由正则表达式给出我认为 XPath 是这里的正确工具，但在细节上是魔鬼.

Also more advanced question: I need to extract all name:value pairs from the XML file then the name is given by regular expression I am thinking that XPath is the right tool here, but devil in details.

推荐答案

您可以使用作为 Java SE 5 一部分包含的 javax.xml.xpath API:

You can use the javax.xml.xpath APIs that are included as part of Java SE 5:

import java.io.FileReader;

import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathFactory;

import org.xml.sax.InputSource;

public class Demo {

    public static void main(String[] args) throws Exception {
        XPathFactory xpf = XPathFactory.newInstance();
        XPath xpath = xpf.newXPath();
        XPathExpression xpe = xpath.compile("//bb[name/text()='k2']/value");

        InputSource xml = new InputSource(new FileReader("input.xml"));
        String result = xpe.evaluate(xml);
        System.out.println(result);
    }
}

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