仅重命名第一个子元素 [英] Renaming first child elements only

问题描述

我想用 XSL 选择并重命名第一个子元素.但它并不是真正的第一个孩子，它更像是第一个孩子的第一个节点.

I want to select and rename the first child element with an XSL. But it's not really the first child, it's more like the first node of the first child.

XML 如下所示:

<Root><Story>
 <CL>
  <BK>
   <name>...</name>
   <Address>...</Address>
  </BK> 
  <BK>
   <name>...</name>
   <Address>...</Address>
 </BK> 
 <BK>
   <name>...</name>
   <Address>...</Address>
  </BK> 
 </CL>
 <CL>
  <BK>
   <name>...</name>
   <Address>...</Address>
  </BK> 
  <BK>
   <name>...</name>
   <Address>...</Address>
 </BK> 
 <BK>
   <name>...</name>
   <Address>...</Address>
  </BK> 
 </CL>
</Story></Root>

我需要之后的第一个元素被重命名，比如而离开其他 元素原样:

I need the first <name> element after <CL> to be renamed, such as <name1> while leaving the other <name> elements as is:

<Root><Story>
 <CL>
  <BK>
   <name1>...</name1>
   <Address>...</Address>
  </BK> 
  <BK>
   <name>...</name>
   <Address>...</Address>
 </BK> 
 <BK>
   <name>...</name>
   <Address>...</Address>
  </BK> 
 </CL>
 <CL>
  <BK>
   <name1>...</name1>
   <Address>...</Address>
  </BK> 
  <BK>
   <name>...</name>
   <Address>...</Address>
 </BK> 
 <BK>
   <name>...</name>
   <Address>...</Address>
  </BK> 
 </CL>
</Story></Root>

推荐答案

这是一个完整而简短的解决方案:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>

 <xsl:template match="BK[1]/name">
  <name1>
   <xsl:apply-templates select="@*|node()"/>
  </name1>
 </xsl:template>
</xsl:stylesheet>

当此转换应用于提供的 XML 文档时:

<Root><Story>
     <CL>
      <BK>
       <name>...</name>
       <Address>...</Address>
      </BK>
      <BK>
       <name>...</name>
       <Address>...</Address>
     </BK>
     <BK>
       <name>...</name>
       <Address>...</Address>
      </BK>
     </CL>
     <CL>
      <BK>
       <name>...</name>
       <Address>...</Address>
      </BK>
      <BK>
       <name>...</name>
       <Address>...</Address>
     </BK>
     <BK>
       <name>...</name>
       <Address>...</Address>
      </BK>
     </CL>
</Story></Root>

产生了想要的、正确的结果:

<Root>
   <Story>
      <CL>
         <BK>
            <name1>...</name1>
            <Address>...</Address>
         </BK>
         <BK>
            <name>...</name>
            <Address>...</Address>
         </BK>
         <BK>
            <name>...</name>
            <Address>...</Address>
         </BK>
      </CL>
      <CL>
         <BK>
            <name1>...</name1>
            <Address>...</Address>
         </BK>
         <BK>
            <name>...</name>
            <Address>...</Address>
         </BK>
         <BK>
            <name>...</name>
            <Address>...</Address>
         </BK>
      </CL>
   </Story>
</Root>

说明:

实际需要的是重命名任何元素的第一个 BK 元素的 name 子元素(在本例中为 CL)有 BK 个孩子.

What actually is wanted is to rename the name child of the first BK element of any element (in this case just CL) that has BK children.

1. 身份规则按原样"复制每个匹配的节点(为其选择执行).

1. The identity rule copies every matched node (for which it is selected for execution) "as-is".

身份模板被匹配任何 name 元素的单个模板覆盖，该元素是 BK 元素的子元素，该元素是其父元素的第一个子元素.这里生成了一个 name1 元素，并且它的属性和正文通过应用模板原样复制(因为它们由唯一的其他模板匹配和处理 - 身份规则).

The identity template is overridden by a single template matching any name element that is a child of a BK element that is the first child of its parent. Here a name1 element is generated and its attributes and body are copied unchanged by just applying templates (because they are matched and processed by the only other template -- the identity rule).

这篇关于仅重命名第一个子元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！