基于特征属性的 XSLT 嵌套菜单转换 [英] XSLT nested menu transform based on featured attribute

问题描述

我正在编写一个将修改现有菜单输出的应用程序.我有很多方法可以想到做到这一点，我认为其中之一是 XSLT，但我是此类转换的完全初学者.

I am writing an application that will modify existing menu output. I have a number of ways I can think of to do this, one of them I think is XSLT but I am a complete beginner in such transforms.

我希望更改以下内容:

<ul>
  <li><a href="#">Item1</a>
    <ul>
      <li class="featured"><a href="#">Item 1.1</a></li>
      <li><a href="#">Item 1.2</a></li>
      <li class="featured"><a href="">Item 1.3</a></li>
      <li><a href="#">Item 1.4</a></li>
    </ul>
  </li>
</ul>

新的:

<ul>
  <li><a href="#">Item1</a>
    <ul>
      <li>
        <ul>
          <li><a href="#">Item 1.1</a></li>
          <li><a href="#">Item 1.2</a></li>
          <li><a href="#">Item 1.3</a></li>
          <li><a href="#">Item 1.4</a></li>
        </ul>
      </li>
      <li>
        <ul class="featured">
           <li><a href="#">Item 1.1</a></li>
           <li><a href="#">Item 1.3</a></li>
        </ul>
      </li>
    </ul>
  </li>
</ul>

我有以下问题:

我需要什么转换才能实现上述目的?

What transform would I need for the above?

我将如何限制为仅 n 级深度(在这种情况下，我们不希望包含 ul.ul.ul.li 项的子项，即项 xx)?

How would I constrain to only n-levels deep (in this case we would not want children of the ul.ul.ul.li items, i.e. Item x.x, to be included)?

如果我只想将此转换应用于顶部 <ul> 具有属性 class="style1" 的样式，并且如果它已设置，该怎么办对 "style2" 应用了不同的转换?

What if I wanted to only apply this transform to a style where the top <ul> has an attribute class="style1", and if it is set to "style2" a different transform is applied?

推荐答案

我不是 100% 确定您为什么要添加额外级别的 ul 并且我不确定n-levels"的深层要求(一个更好的例子会有所帮助)，但这应该会让你开始:

I'm not 100% sure why you are adding an extra level of ul and I'm not sure about the "n-levels" deep requirement (a better example would help), but this should get you started:

XSLT 1.0

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output indent="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="ul[@class='style1']/li">
        <xsl:copy>
            <xsl:apply-templates select="@*|*[not(self::ul)]"/>
            <ul>
                <li>
                    <xsl:apply-templates select="ul"/>
                </li>
                <li>
                    <ul class="featured">
                        <xsl:apply-templates select="ul/li[@class='featured']"/>
                    </ul>
                </li>
            </ul>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="li">
        <xsl:copy>
            <xsl:apply-templates/>
        </xsl:copy>
    </xsl:template>

</xsl:stylesheet>

输出

<ul class="style1">
   <li>
      <a href="#">Item1</a>
      <ul>
         <li>
            <ul>
               <li>
                  <a href="#">Item 1.1</a>
               </li>
               <li>
                  <a href="#">Item 1.2</a>
               </li>
               <li>
                  <a href="">Item 1.3</a>
               </li>
               <li>
                  <a href="#">Item 1.4</a>
               </li>
            </ul>
         </li>
         <li>
            <ul class="featured">
               <li>
                  <a href="#">Item 1.1</a>
               </li>
               <li>
                  <a href="">Item 1.3</a>
               </li>
            </ul>
         </li>
      </ul>
   </li>
</ul>

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