为什么此 XSL 无法检索值? [英] Why does this XSL fails to retrieve value?
问题描述
以下是我编写的XSL 样式表的摘录.它说我的 '.xsl' 格式正确，但它不从 XML 中检索值，而只是粘贴标题和表格标题.
Following is an extract of the XSL stylesheet that I have written. It says my '.xsl' is well formed but it somehow does not retrieve values from the XML, instead just pastes the header and table headings.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:template match="/" >
<html>
<head>
<title>GlenMark Pharma</title>
</head>
<h1 align="center"><font face="Monotype Corsiva" color="red">GlenMarkPharma</font></h1>
<body>
<table>
<tbody>
<tr>
<th>ID</th>
<th>ENAME</th>
<th>Mobile</th>
<th>EMAIL</th>
<th>PWD</th>
</tr>
<xsl:for-each select="employees/employee">
<tr>
<td><xsl:value-of select="@empID" /></td>
<td><xsl:value-of select="name" /></td>
<td><xsl:value-of select="mobile" /></td>
<td><xsl:value-of select="email" /></td>
<td><xsl:value-of select="pwd" /></td>
</tr>
</xsl:for-each>
</tbody>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
这是我的 XML 文档:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="MyfirstXsl.xsl"?>
<!DOCTYPE employees SYSTEM "Mydtd.dtd">
<me:employees xmlns:me="pavitar.dua@gmail.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="pavitar.dua@gmail.com Mycomplex.xsd">
<me:employee empID="EMP101">
<me:name>Vicky</me:name>
<me:mobile>9870582356</me:mobile>
<me:email>vicky@gmail.com</me:email>
<me:pwd>&defPWD;</me:pwd>
</me:employee>
</me:employees>
我也尝试过写作:
<xsl:for-each select="employees/employee">
<tr>
<td><xsl:value-of select="@empID" /></td>
<td><xsl:value-of select="me:name" /></td>
在 XSL 中，因为我的 XML 文档中有一个名称空间的别名.但它给了我无效前缀的错误.我不知道我做错了什么.
In the XSL since I have an alias to the namespace in my XML Doc.But it gives me an error of Invalid Pre-fix.I don't know what I'm doing wrong.
推荐答案
在 XSLT 中添加两个命名空间声明:
Add two namespace declarations into your XSLT:
xmlns:me="pavitar.dua@gmail.com"表示输入标记；xmlns="http://www.w3.org/1999/xhtml"表示结果标记.
xmlns:me="pavitar.dua@gmail.com"to denote the input marktup;xmlns="http://www.w3.org/1999/xhtml"to denote the resulting markup.
然后更改您的 XSLT 以使用 me 前缀表示源，如下所示:
And then change your XSLT to denote the source with the me prefix like this:
<xsl:for-each select="me:employees/me:employee">
<tr>
<td><xsl:value-of select="@empID" /></td>
<td><xsl:value-of select="me:name" /></td>
<td><xsl:value-of select="me:mobile" /></td>
<td><xsl:value-of select="me:email" /></td>
<td><xsl:value-of select="me:pwd" /></td>
</tr>
</xsl:for-each>
此外，请考虑使用更多 XSLT 原生"结构:
Also, consider using a "more XSLT-native" constructs:
<xsl:apply-templates/> <!-- instead of the for-each --!>
…
<xsl:template match="me:employee">
<!-- include the table row here --!>
</xsl:template>
您最终会得到更通用的 XSLT 设计.请记住，XSLT 应该是声明性而不是程序性的.
You will end up with a more versatile XSLT design. Bear in mind that XSLT is supposed to be declarative not procedural.
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