XML 解析问题 [英] XML parsing problems

问题描述

我需要解析这个，这样我才能得到MMV的属性和所有CS标签的所有属性

i need to parse this such that i can get the attribute of MMV and all the attributes of all CS tags

<MMV val="Configdes000110010101">  
  <CS protocol="SNMP" CommandString="wmanIfBsDcdInterval" 
      oid="1.3.6.1.2.1.10.184.1.1.2.2.1.1" Get_SecurityString="public" 
      Set_SecurityString="public" type="INTEGER" > </CS>  
  <CS protocol="SNMP" CommandString="wmanIfBsUcdInterval" 
      oid="1.3.6.1.2.1.10.184.1.1.2.2.1.2" Get_SecurityString="public" 
      Set_SecurityString="public" type="INTEGER" > </CS>  
  <CS protocol="SNMP" CommandString="wmanIfBsUcdTransition" 
      oid="1.3.6.1.2.1.10.184.1.1.2.2.1.3" Get_SecurityString="public" 
      Set_SecurityString="public" type="INTEGER" > </CS>  
  <CS protocol="SNMP" CommandString="wmanIfBsDcdTransition" 
      oid="1.3.6.1.2.1.10.184.1.1.2.2.1.4" Get_SecurityString="public"  
      Set_SecurityString="public" type="INTEGER" > </CS>  
</MMV>

推荐答案

您将需要一个 XML 解析器，最好是一个支持 XPath 的引擎.我使用 XOM (Java) http://www.xom.nu 并且会写一个类似于

you will need an XML parser and preferably an engine that supports XPath. I use XOM (Java) http://www.xom.nu and would write an XPath expression something like

Nodes attributes = document.query("//MMV@*");

这将给出所有 MMV 属性的所有属性.同理

which would give all the attributes of all the MMV attributes. Similarly

Nodes attributes = document.query("//CS@*");

发布 XML 后的更新

Node valAttribute = document.query("MMV@val").get(0); 

并且 CS 版本应该仍然有效或

and the CS version should still work or

Nodes csAttributes = document.query("MMV/CS@*");

这也可以通过 XSLT 来完成.

Alternatively this could be done with XSLT.

注意:您要求的是属性；您实际上可能只想要属性值

NOTE: You ask for the attributes; you may actually want only the attribute values

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