XMPPFramework - 如何获取在线和离线好友列表? [英] XMPPFramework - How can I get a list of online and offline friends?

问题描述

如何在 iOS 中使用 XMPPFramework 获取在线和离线好友列表?

How can I get a list of online and offline friends using XMPPFramework in iOS?

我想向用户发送好友请求.那么我怎样才能做到这一点呢?有人可以为我分享一些示例代码吗?

I want to send buddy request to user. So how can I achieve this? Can somebody share some sample codes for me?

谢谢.

推荐答案

通过使用这些方法，您将收到整个用户在线/离线、添加、删除、更新等的通知.通过使用这些方法您可以更新您的联系人列表

By using these methods you will get notified whole a user going to online/ offline, added, removed , updated etc.by using these methods you can update your contact list

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didAddUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didUpdateUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didRemoveUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
    didAddResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
 didUpdateResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
 didRemoveResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

//添加好友

- (void)addContactWithUserName:(NSString *)userName andNickName:(NSString *)nickName;
{
    if(userName)
    {
        XMPPJID *jid = [XMPPJID jidWithString:[NSString stringWithFormat:@"%@@%@",userName,self.hostName]];
        if(nickName)
        {
            [_xmppRoster addUser:jid withNickname:nickName];
        }
        else
        {
            [_xmppRoster addUser:jid withNickname:nil];
        }
    }
else
{
    NSLog(@"missing userName");
}
}

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