jqGrid的editurl:控制器操作参数 [英] jqgrid editurl : controller action parameters
问题描述
当我在使用的jqGrid属性editurl后,我打提交关于增加一个新行按钮控制器动作被调用。但是,我怎么得到的所有网格行吗?其中参数应该从我的控制器的操作方法,以获得电网数据读取?
格code:
$(#list1的)。jqGrid的({
网址:'/ CMS / GetCustomLanguageData',
---
---
editurl:'/ CMS / SaveCustomLanguageData
---
添加新行code:
grid.jqGrid('editGridRow,新,{身高:280,reloadAfterSubmit:假的,addCaption:添加记录,
editCaption:编辑记录,
bSubmit:提交,
bCancel:取消,
BCLOSE:关闭,
SAVEDATA:数据已更改保存更改!?
再见:是的,
BNO:否
});
控制器code:
公众的ActionResult SaveCustomLanguageData()
{
}
的jqGrid发送到与该名称命名的参数控制器作为你的名称属性定义 colModel
。此外将发送 OPER =添加
和 ID = _empty
。所以,你的控制器动作可以像下面
公共JsonResult SaveCustomLanguageData(串号,串OPER,为MyObject项)
{
//测试ID为_empty或oper为增加。
//如果是这样添加的项目,并返回新的ID值
//例如返回JSON(123);
}
在客户端,你应该去code例如具有以下code
JSON响应 jQuery.extend(jQuery.jgrid.edit,{
afterSubmit:功能(响应,POSTDATA){
返回[真,,jQuery.parseJSON(response.responseText)];
}
});
When I use editurl property in my jqgrid, the controller action gets called after I hit submit button on adding a new row. But how do I get all the grid rows there? Which parameter should I read from my controller action method in order to get the grid data?
Grid code:
$("#list1").jqGrid({
url: '/CMS/GetCustomLanguageData',
---
---
editurl: '/CMS/SaveCustomLanguageData'
---
Add new row code:
grid.jqGrid('editGridRow',"new",{height:280,reloadAfterSubmit:false,addCaption: "Add Record",
editCaption: "Edit Record",
bSubmit: "Submit",
bCancel: "Cancel",
bClose: "Close",
saveData: "Data has been changed! Save changes?",
bYes : "Yes",
bNo : "No"
});
Controller code:
public ActionResult SaveCustomLanguageData()
{
}
jqGrid send to the controller named parameters with the name as you defined in the 'name' property of the colModel
. Additionally will be send oper=add
and id=_empty
. So your controller action can look like following
public JsonResult SaveCustomLanguageData (string id, string oper, MyObject item)
{
// test id for "_empty" or oper for "add".
// If so add the item and return the value of the new id
// for example return Json ("123");
}
on the client side you should decode the JSON response for example with the following code
jQuery.extend(jQuery.jgrid.edit, {
afterSubmit: function (response, postdata) {
return [true, "", jQuery.parseJSON(response.responseText)];
}
});
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