XPage 视图控件链接操作 [英] XPages view control link manipulation

问题描述

我有一个视图控件，并且至少有一列设置了显示为链接"选项.该链接是手动生成的.我想要实现的是添加一个添加到视图列链接的 url 参数.通常的链接是这样的

I have a view control and at least one column has the option "Display as link" set. The link is generated manually. What I want to achieve is to add a url parameter which is added to a view column link. The usual link would like this

"http://host/path/file.nsf/$$OpenDominoDocument.xsp?databaseName=server!!path/file.nsf&documentId=03871DD0B47F88D4C12576AB00623137&action=editDocument"

"http://host/path/file.nsf/$$OpenDominoDocument.xsp?databaseName=server!!path/file.nsf&documentId=03871DD0B47F88D4C12576AB00623137&action=editDocument"

我想要的是:

"http://host/path/file.nsf/$$OpenDominoDocument.xsp?databaseName=server!!path/file.nsf&documentId=03871DD0B47F88D4C12576AB00623137&action=editDocument?param1=value1&param2=value2&param2=value2&param2……"

"http://host/path/file.nsf/$$OpenDominoDocument.xsp?databaseName=server!!path/file.nsf&documentId=03871DD0B47F88D4C12576AB00623137&action=editDocument?param1=value1&param2=value2&etc..."

必须有一种(大概是简单的)方法来实现这一点 - 不幸的是我不知道如何......任何帮助或提示表示赞赏.

There must be a (presumably easy) way to achieve this - unfortunately I don't know how... Any help or hint is appreciated.

非常感谢.迈克尔

推荐答案

请按照以下步骤操作:1. 转到查看列的所有属性，该列将列值显示为链接.2. 使用以下代码计算 PageUrl.

Follow the below steps: 1. go to All Properties of view Column which displays column values as link. 2. Compute the PageUrl with the below Code.

    var col:com.ibm.xsp.component.xp.XspViewColumn = getComponent("viewColumn1");
col.getDocumentUrl()+"&param1=value1"

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