选择不包含在其他类型元素中的后代元素 [英] Select descendant elements that are not contained in another type of element

问题描述

在 XPath 1.0 中，如何选择当前(上下文)节点 A 的所有后代节点 C，这些子节点不包含在类型 B 的中间节点中?

例如，查找当前元素中包含的所有 链接，这些链接不在

内.但是如果当前元素本身在

中，那就无关紧要了.

<——这无关紧要，因为它在当前元素之外...<div><—— 当前元素(上下文节点)...<a></a><—— xpath 应该选择这个节点...<p>...<a></a><—— 但不是这个，因为它在一个 p 中，它在上下文中...<p>...

...</p>

示例中的 ... 可以是多个深度的中间节点.

我正在编写 XSLT 1.0，因此可以使用附加函数 generate-id()、current() 等.

解决方案

这是一种可能的 XPath :

.//a[not(ancestor::p/​​ancestor::* = current())]

此 XPath 检查当前后代 a 元素是否没有祖先 p，而祖先是当前上下文节点.换句话说，它检查 a 元素是否没有祖先 p 介入 a 和当前上下文节点之间.

In XPath 1.0, how can I select all descendant nodes C of current (context) node A, that are not contained in an intervening node of type B?

For example, find all <a> links contained in the current element, that are not inside a <p>. But if the current element is itself inside a <p>, that's irrelevant.

<p>                   <—— this is irrelevant, because it's outside the current element
    ...
    <div>             <—— current element (context node)
        ...
        <a></a>       <—— the xpath should select this node
        ...
        <p>
            ...
            <a></a>   <—— but not this, because it's inside a p, which is inside context
            ...
        <p>
        ...
    </div>
    ...
</p>

The ... in the example could be several depths of intervening nodes.

I'm writing XSLT 1.0, so the additional functions generate-id(), current(), and such are available.

解决方案

This is one possible XPath :

.//a[not(ancestor::p/ancestor::* = current())]

This XPath checks if current descendant a element doesn't have ancestor p which ancestor is current context node. In other words, it checks if the a element doesn't have ancestor p intervening between the a and the current context node.

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