XSLT/XPATH - 查找列数最多的表格行 [英] XSLT/XPATH - Find table row with the most columns

问题描述

我正在将 xml 表转换为不同的表规范，我需要确定给定表中任何行中存在的最大列数.所以如果我的 XML 是:

I'm transforming an xml table to a different table spec, and I need to determine the maximum number of columns that are present in any row in a given table. So if my XML is:

<table>
    <row>
        </column>
    </row>
    <row>
        </column>
        </column>
        </column>
    </row>
    <row>
        </column>
        </column>
    </row>  
</table>

我需要在表格模板中将3"作为变量，以便我可以按如下方式重写表格:

I need to get "3" as a variable in my table template so that I can rewrite the table as follows:

<table cols="3">
...

我正在做这个，这很愚蠢(但刚好够用......).

I'm doing this, which is very dumb (but just good enough...).

    <xsl:template match="table">        
        <xsl:variable name="high_col_count">
            <xsl:choose>
                ...
                <xsl:when test="tr/td[position()=4]">4</xsl:when>
                <xsl:when test="tr/td[position()=3]">3</xsl:when>
                <xsl:when test="tr/td[position()=2]">2</xsl:when>
                ...
            </xsl:choose>
        </xsl:variable>
    ...
</xsl:template>

我无法确定更好的方法是在不迭代变量的情况下执行此操作，据我所知，由于变量是不可变的，因此在 xslt 中这是不可能的.有没有更简单的方法可以简单地从列数最多的行中检索计数?

I can't determine a better was to do this without iterating over a variable, which as I understand isn't possible in xslt due to variables being immutable. Is there an easier way to simply retrieve the count from the row with the most columns?

推荐答案

尝试改用这个:

<xsl:template match="table">
  <table cols="{max(row/count(column))}">
  ...
  </table>
</xsl:template>

这篇关于XSLT/XPATH - 查找列数最多的表格行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！