使用 xpath 获取所有属性值 [英] get to all attribute value using xpath
本文介绍了使用 xpath 获取所有属性值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
这是我的 xml 文件:-
<结果值="111"><Country_Code value="IN"/><Country_Name value="印度"/><Region_Name value="古吉拉特"/><城市价值="拉杰科特"/><location lat="13.060422" lng="80.24958300000003"/></结果><结果值="222"><Country_Code value="KE"/><Country_Name value="肯尼亚"/><Region_Name value="Vihiga"/><City value="Kakamega"/><location lat="0.1182473" lng="34.7334515999997"/></结果></结果> 这是我的代码:-
<头><script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script><脚本>var xml;$.get("sea.xml",空值，功能(数据){xml = 数据；},xml");函数 get_list(ls) {var elName = $('#select').val();var value = $('#value').val();if(elName == "" || value == ""){}else if (elName != "" || value != ""){var xPath = '//*[ @lat '+ ls +' "'+elName+'" 和@lng '+ ls +' "'+value+'"]'+'/../City/@*';var iterator = xml.evaluate(xPath, xml.documentElement, null,XPathResult.UNORDERED_NODE_ITERATOR_TYPE, null);var thisNode = iterator.iterateNext();var str = '';而(这个节点){如果(字符串){str += ', ';}str += thisNode.textContent;thisNode = iterator.iterateNext();}$("#result").text(str);}别的{}}<身体><input type="text" id="select"><input type="text" id="value"><input type="button" name="button" value="Search" onclick="get_list('=')"><div id="结果"></html>
使用此代码 xpath 返回属性值 Rajkot 但我想在 Xpath 中更改以获取所有属性
在 xPath 的帮助下，如果 xml 文件上的值匹配，则仅返回城市属性值.
但我想要所有属性值，如:- IN,Inida,Gujarat,Rajkot,13.060422,80.24958300000003
解决方案
以下 XPath:
//location[@lat='13.060422' and @lng='80.24958300000003'][1]/preceding-sibling::City/@value输出:
value="Rajkot"<小时>
以及以下 XPath:
//location[@lat='13.060422' and @lng='80.24958300000003'][1]/preceding-sibling::*/@*输出:
value="IN"-----------------------价值=印度"-----------------------价值=古吉拉特邦"-----------------------价值=拉杰科特"this is my xml file:-
<results value="1">
<result value="111">
<Country_Code value="IN"/>
<Country_Name value="India"/>
<Region_Name value="Gujarat"/>
<City value="Rajkot"/>
<loction lat="13.060422" lng="80.24958300000003"/>
</result>
<result value="222">
<Country_Code value="KE"/>
<Country_Name value="Kenya"/>
<Region_Name value="Vihiga"/>
<City value="Kakamega"/>
<loction lat="0.1182473" lng="34.7334515999997"/>
</result>
</results>
this is my code:-
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script>
var xml;
$.get(
"sea.xml",
null,
function (data) {
xml = data;
},
"xml"
);
function get_list(ls) {
var elName = $('#select').val();
var value = $('#value').val();
if(elName == "" || value == "")
{
}
else if (elName != "" || value != "")
{
var xPath = '//*[ @lat '+ ls +' "'+elName+'" and @lng '+ ls +' "'+value+'"]'+'/../City/@*';
var iterator = xml.evaluate(xPath, xml.documentElement, null,
XPathResult.UNORDERED_NODE_ITERATOR_TYPE, null);
var thisNode = iterator.iterateNext();
var str = '';
while (thisNode) {
if (str) {
str += ', ';
}
str += thisNode.textContent;
thisNode = iterator.iterateNext();
}
$("#result").text(str);
}
else
{}
}
</script>
</head>
<body>
<input type="text" id="select">
<input type="text" id="value">
<input type="button" name="button" value="Search" onclick="get_list('=')">
<div id="result">
</div>
</body>
</html>
with this code xpath return attribute value Rajkot but i want to change in Xpath to get all the attribute
with help of xPath if value match on xml file return only city attribute value.
but i want to all attribute value like:- IN,Inida,Gujarat,Rajkot,13.060422,80.24958300000003
解决方案
The following XPath:
//loction[@lat='13.060422' and @lng='80.24958300000003'][1]/preceding-sibling::City/@value
Outputs:
value="Rajkot"
And the following XPath:
//loction[@lat='13.060422' and @lng='80.24958300000003'][1]/preceding-sibling::*/@*
Outputs:
value="IN"
-----------------------
value="India"
-----------------------
value="Gujarat"
-----------------------
value="Rajkot"
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