在 XML 中直接使用数据类型 [英] Use datatype directly with in XML

问题描述

我正在尝试使用以下 XSD 验证以下 XML:

I'm trying to validate below XML with the below XSD:

XML

<Device xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <Parameter Id="100" Flag="100" xsi:type="xsd:unsignedInt">-100</Parameter>
</Device>

XSD

<?xml version="1.0" encoding="UTF-8" ?>
<xsd:schema xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
        <xsd:element name="Device">
           <xsd:complexType>
                <xsd:sequence>
                   <xsd:element name='Parameter' type='paramType' minOccurs='0' maxOccurs='unbounded' />
                </xsd:sequence>        
           </xsd:complexType>
        </xsd:element>

        <xsd:complexType name="paramType">              
                        <xsd:attribute name="Id" use="required"/>
                        <xsd:attribute name="Flag" use="required"/>
                        <xsd:anyAttribute processContents="lax"/>            
        </xsd:complexType>

</xsd:schema>

我面临两个问题:

无法直接在 XML 中使用 xsd:unsignedInt 并出现以下错误

Unable to use xsd:unsignedInt directly in XML with below error

Type 'xsd:unsignedInt' is not validly derived from the type definition, 'paramType', of element 'Parameter'

无法同时使用 xsd:type 和其他非命名空间属性

Unable to use both xsd:type and other non-namespaced attributes at the same time

Element 'Parameter' is a simple type, so it cannot have attributes, excepting those whose namespace name is identical to 'http://www.w3.org/2001/XMLSchema-instance' and whose [local name] is one of 'type', 'nil', 'schemaLocation' or 'noNamespaceSchemaLocation'. However, the attribute, 'Flag' was found.

如何编辑我的 XSD 以解决这些问题.我的最后一个要求是所有 Parameter 节点都应该包含 Id 和 Flag 属性，并且它的值应该根据提供的类型(在实际的 XML本身).

How do I edit my XSD to fix these issues. My final requirement is that all the Parameter nodes should contain Id and Flag attributes and its value should be validated against type provided (in the actual XML itself).

在 xsd 中使用 xsi:type 不是我的选择.

Using xsi:type inside xsd is not an option for me.

推荐答案

由于 xsi:type 必须从 XSD 中指定的类型派生，并且由于 Parameter在 XSD 中定义为复杂的，您可能想要创建 xsd:anySimpleType 的参数的子项，例如 Value，然后您可以通过 xsd:anySimpleType 成功覆盖它XML 文档中的 code>xsi:type.

Since xsi:type has to be derivable from the type specified in the XSD, and since Parameter is defined in the XSD to be complex, you'll probably want to create a child of Parameter, say Value, of xsd:anySimpleType that you can then override successfully via xsi:type in the XML document.

<?xml version="1.0" encoding="UTF-8"?>
<Device xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <Parameter Id="100" Flag="100">
        <Value xsi:type="xsd:unsignedInt">100</Value>
    </Parameter>
</Device>

XSD

<?xml version="1.0" encoding="UTF-8" ?>
<xsd:schema xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
            xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <xsd:element name="Device">
    <xsd:complexType>
      <xsd:sequence>
        <xsd:element name='Parameter' type='paramType' 
                     minOccurs='0' maxOccurs='unbounded' />
      </xsd:sequence>        
    </xsd:complexType>
  </xsd:element>

  <xsd:complexType name="paramType">              
    <xsd:sequence>
      <xsd:element name="Value" type="xsd:anySimpleType"/>
    </xsd:sequence>
    <xsd:attribute name="Id" use="required"/>
    <xsd:attribute name="Flag" use="required"/>
    <xsd:anyAttribute processContents="lax"/>
  </xsd:complexType>

</xsd:schema>

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