当 XSLT for-each 处于循环中时.如何根据其他 XML 值向该 XML 添加属性或节点.使用 XSLT [英] When XSLT for-each is in a loop. How can I add an attribute or node to that XML based on other XML value. USING XSLT

问题描述

谁能帮我解决这个问题?

Can any one help me to sort this problem?

我有一个 XML 并根据某些条件过滤值.将过滤后的 xml 存储在变量中.在过滤条件时，我试图向过滤后的 xml 添加一个属性或节点，但它对我不起作用..

I have an XML and filtering the values based on some condition. Storing the filtered xml in a variable. While filtering the condition, I'm trying to add an attribute or node to the filtered xml but it is not working for me..

输入 XML:

    <root>
        <a id="13">
            <b>XXX1</b>
            <c>YYY1</c>
        </a>
        <a id="2">
            <b>XXX2</b>
            <c>YYY2</c>
        </a>
        <a id="15">
            <b>XXX3</b>
            <c>YYY3</c>
        </a>
        <a id="37">
            <b>XXX4</b>
            <c>YYY4</c>
        </a>
        <a id="51">
            <b>XXX5</b>
            <c>YYY5</c>
        </a>
    </root>

另一个存储在名为data"的变量中的 XML(用于过滤):

Another XML which is stored in a variable called "data" (this is for filtering):

<sample>
    <con id="37" order="1"/>
    <con id="13" order="2"/>
    <con id="51" order="3"/>
    <con id="2" order="4"/>
    <con id="15" order="5"/>
</sample>

使用 XSLT，我试图过滤 &以这种方式添加元素.

Using XSLT, I'm trying to filter & add a element in this way.

<xsl:variable name="filteredData">
    <newroot>
      <xsl:for-each select="/root/a[@id > 14]">
        <xsl:if test="msxsl:node-set($data)/sample/con[@id = current()/@id]/@id = current()/@id">
          <xsl:element name="order">
            <xsl:value-of select="msxsl:node-set($data)/sample/con[@id = current()/@id]/@order"/>
          </xsl:element>
        </xsl:if>
      </xsl:for-each>
    </newroot>
</xsl:variable>

输出 XML(即filteredData"变量应包含以下 XML):

OUTPUT XML (i.e., "filteredData" variable should contain below XML):

     <newroot>
        <a id="15">
            <b>XXX3</b>
            <c>YYY3</c>
            <order>5</order>
        </a>
        <a id="37">
            <b>XXX4</b>
            <c>YYY4</c>
            <order>1</order>
        </a>
        <a id="51">
            <b>XXX5</b>
            <c>YYY5</c>
            <order>3</order>
        </a>
    </newroot>

推荐答案

尝试使用具有键函数的查找表，如本例所示 提示:XSLT 查找表

Try using a lookup table with the key function as in this example Tip: XSLT Lookup Table

我能够获得以下代码段来生成与上面的输出匹配的 xml 文档.下面的 xslt 中的过滤数据是从一个单独的文档中加载的，但应该很容易适应.

I was able to get the following snippet to produce an xml document which matched your output above. The filtering data in the xslt below has been loaded from a separate document but it should be easy to adapt.

<xsl:key name="id-lookup" match="con" use="@id"/>

<xsl:variable name="id-top" select="document('<lookup file>')/sample"/>

<xsl:template match="root">
    <newroot>
        <xsl:for-each select="a[@id > 14]">
            <xsl:copy>
                <xsl:copy-of select="@*|node()"/>

                <xsl:element name="order">
                    <xsl:apply-templates select="$id-top">
                        <xsl:with-param name="curr-label" select="."/>
                    </xsl:apply-templates>
                </xsl:element>
            </xsl:copy>
        </xsl:for-each>
    </newroot>
</xsl:template>


<xsl:template match="sample">
    <xsl:param name="curr-label"/>
    <xsl:value-of select="key('id-lookup', $curr-label/@id)/@order"/>
</xsl:template>

这篇关于当 XSLT for-each 处于循环中时.如何根据其他 XML 值向该 XML 添加属性或节点.使用 XSLT的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！