取所有元素不同而不重复 xslt 1.0 [英] Take all element distinct without repetition xslt 1.0

问题描述

从我的 XML 代码中，我想一次获取所有项目而不重复.我的 XML 代码是:

From My XML code I want to take all of the items at once without repetition. My Xml code is:

      <NTC_LIGHTLISTPRODUCT>
         <IMMUTABLE_ID>9814</IMMUTABLE_ID>
         <LIGHT_DESCRIPTION_LIST>             
            <LIGHT_DESCRIPTION>                  
              <LIGHT_SUPPORT_HEIGHT>198</LIGHT_SUPPORT_HEIGHT>
            </LIGHT_DESCRIPTION>
            <LIGHT_DESCRIPTION>                  
              <LIGHT_SUPPORT_HEIGHT>166</LIGHT_SUPPORT_HEIGHT>
            </LIGHT_DESCRIPTION>
            <LIGHT_DESCRIPTION>                  
              <LIGHT_SUPPORT_HEIGHT>122</LIGHT_SUPPORT_HEIGHT>
            </LIGHT_DESCRIPTION>
            <LIGHT_DESCRIPTION>                  
              <LIGHT_SUPPORT_HEIGHT>76</LIGHT_SUPPORT_HEIGHT>
            </LIGHT_DESCRIPTION>
            <LIGHT_DESCRIPTION>                  
              <LIGHT_SUPPORT_HEIGHT>31</LIGHT_SUPPORT_HEIGHT>
            </LIGHT_DESCRIPTION>
            <LIGHT_DESCRIPTION>                  
              <LIGHT_SUPPORT_HEIGHT>31</LIGHT_SUPPORT_HEIGHT>
            </LIGHT_DESCRIPTION>              
         </LIGHT_DESCRIPTION_LIST>
      <NTC_LIGHTLISTPRODUCT>

我想要序列:198 166 122 76 31.

I want the sequence: 198 166 122 76 31.

我写了这段代码 xslt 1.0，但我无法得到正确的结果:

I wrote this code xslt 1.0, but I can not get a correct result:

<xsl:for-each select="LIGHT_DESCRIPTION">
    <xsl:for-each select="LIGHT_SUPPORT_HEIGHT">
        <xsl:if test=".=not(preceding::LIGHT_SUPPORT_HEIGHT[1][preceding::IMMUTABLE_ID=$EF])">
            <span style="font-size:9pt; text-align:center; ">
                <xsl:value-of select="."/>
            </span>
        </xsl:if>
</xsl:for-each>

EF 是当前节点的变量(不可变 ID)，我用它来保持在这个节点内.

EF is a variable of current node (IMMUTABLE ID) and I use this to remain inside this node.

你"能给我更多的指示吗?谢谢

Can "you" give me more instructions? THANKS

推荐答案

在 XSLT 1.0 中对此类问题进行分组的标准方法称为Muenchian 分组"——本质上您定义了一个对节点进行分组的 键应该被视为相同"，然后使用带有 generate-id 的技巧来处理每个组中的第一个节点.

The standard approach to grouping problems like this in XSLT 1.0 is called "Muenchian grouping" - essentially you define a key that groups nodes that should be treated as "the same", and then use a trick with generate-id to process just the first node in each group.

在这种情况下，分组约束是 LIGHT_SUPPORT_HEIGHT 值本身和包含 NTC_LIGHTLISTPRODUCT 的 IMMUTABLE_ID 的值的组合:

In this case the grouping constraint is a combination of the LIGHT_SUPPORT_HEIGHT value itself, and the value of the containing NTC_LIGHTLISTPRODUCT's IMMUTABLE_ID:

<xsl:key name="supportHeightKey" match="LIGHT_SUPPORT_HEIGHT"
    use="concat(., '|', ancestor::NTC_LIGHTLISTPRODUCT[1]/IMMUTABLE_ID)" />

现在您可以使用

<!-- assuming the current context is LIGHT_DESCRIPTION_LIST -->
<xsl:for-each select="LIGHT_DESCRIPTION/LIGHT_SUPPORT_HEIGHT[
     generate-id() = generate-id(
        key('supportHeightKey', concat(., '|', current()/../IMMUTABLE_ID))[1])]">
  <span style="font-size:9pt; text-align:center; ">
    <xsl:value-of select="."/>
  </span>
</xsl:for-each>

这篇关于取所有元素不同而不重复 xslt 1.0的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！