尽管在模板中给出了后代匹配，但未捕获 [英] descendant match not caught though given in template
问题描述
我有以下 XML
<list.item><label>3.7.8</label><emphasis type="italic">健康影响</emphasis></list.item><list.item><label>3.7.8.1</label>一个健康</list.item><list.item><label><star.page>216</star.page>3.7.8.2健康风险评估应包括以下关键步骤:<列表><list.item><label>(i)</label>一个系统的识别</list.item><list.item><label>(ii)</label>评估</list.item><list.item><label>(iii)</label></list.item><list.item><label>(iv)</label>推荐</list.item></list></list.item><list.item><label>3.7.8.3</label>健康</list.item><list.item><label>3.7.8.4</label>环境健康来源.</list.item><list.item><label>3.7.8.5</label>这也是必要的电子项目.(强调)</list.item></list>
和下面的 XSL
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"><xsl:output method="html"/><xsl:template match="/"><身体><xsl:apply-templates select="root"/></html></xsl:模板><xsl:template match="root"><xsl:apply-templates select="list"/></xsl:模板><xsl:template name="orderedlist" match="list"><xsl:variable name="strl"><xsl:value-of select="descendant::list.item/label/string-length(./text())"/></xsl:变量><!--<xsl:value-of select="$strl"/>--><xsl:when test="normalize-space($strl) >'7'"><ol class="eng-orderedlistorderedlist1"><xsl:apply-templates/></ol></xsl:when><xsl:否则><ol class="eng-orderedlistorderedlist"><xsl:apply-templates/></ol></xsl:否则></xsl:选择></xsl:模板><xsl:template name="orderitem" match="list.item"><xsl:apply-templates select="./label/node()[1][self::star.page]" mode="first"/><li class="item"><div class="para"><xsl:if test="./label"><span class="item-num"><xsl:value-of select="./label/text()"/></span></xsl:if><xsl:when test="./text()"><xsl:apply-templates select="child::node()[not(self::label)]"/></xsl:when><xsl:否则><xsl:text> </xsl:text></xsl:否则></xsl:选择> </xsl:模板></xsl:stylesheet>
这里我提到了 <xsl:value-of select="descendant::list.item/label/string-length(./text())"/> 并在如果它的值超过七个字符，我给出的条件应该采用 orderedlist 否则应该采用 orderedlist1.
这里的条件是在当前列表中，如果有任何label长度大于7(当前列表中的任何标签)，则取orderedlist1，否则 有序列表.请让我知道我哪里出错了，我该如何解决这个问题.
谢谢
我会把你的描述在当前列表中，如果有任何长度大于 7 的标签"翻译成 <xsl:if test="descendant::list.item/label[string-length() gt 7]">...</xsl:if>.
I've the below XML
<list>
<list.item><label>3.7.8</label> <emphasis type="italic">Health Impact</emphasis></list.item>
<list.item><label>3.7.8.1</label> A health </list.item>
<list.item><label><star.page>216</star.page> 3.7.8.2</label> The health risk assessment shall include the following key steps:
<list>
<list.item><label>(i)</label> a systematic identification</list.item>
<list.item><label>(ii)</label> an assessment</list.item>
<list.item><label>(iii)</label> an </list.item>
<list.item><label>(iv)</label> recommendation </list.item>
</list>
</list.item>
<list.item><label>3.7.8.3</label> The health </list.item>
<list.item><label>3.7.8.4</label> The environmental health sources.</list.item>
<list.item><label>3.7.8.5</label> It is also necessary e Project. (emphasis supplied)</list.item>
</list>
and the below XSL
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output method="html"/>
<xsl:template match="/">
<html>
<body>
<xsl:apply-templates select="root"/>
</body>
</html>
</xsl:template>
<xsl:template match="root">
<xsl:apply-templates select="list"/>
</xsl:template>
<xsl:template name="orderedlist" match="list">
<xsl:variable name="strl">
<xsl:value-of select="descendant::list.item/label/string-length(./text())"/>
</xsl:variable>
<!--<xsl:value-of select="$strl"/>-->
<xsl:choose>
<xsl:when test="normalize-space($strl) > '7'">
<ol class="eng-orderedlist orderedlist1">
<xsl:apply-templates/>
</ol>
</xsl:when>
<xsl:otherwise>
<ol class="eng-orderedlist orderedlist">
<xsl:apply-templates/>
</ol>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="orderitem" match="list.item">
<xsl:apply-templates select="./label/node()[1][self::star.page]" mode="first"/>
<li class="item">
<div class="para">
<xsl:if test="./label">
<span class="item-num">
<xsl:value-of select="./label/text()"/>
</span>
</xsl:if>
<xsl:choose>
<xsl:when test="./text()">
<xsl:apply-templates select="child::node()[not(self::label)]"/>
</xsl:when>
<xsl:otherwise>
<xsl:text> </xsl:text>
</xsl:otherwise>
</xsl:choose>
</div>
</li>
</xsl:template>
</xsl:stylesheet>
here I've mentioned <xsl:value-of select="descendant::list.item/label/string-length(./text())"/> and in condition i gave if its value is more than seven chars, it should take orderedlist else should take orderedlist1.
Here the condition is in the current list, if there are any label whose length is greater than 7(any label in current list), it should take orderedlist1, else orderedlist.
please let me know where am i going wrong and how can i fix this.
Thanks
I would translate your description "in the current list, if there are any label whose length is greater than 7" into <xsl:if test="descendant::list.item/label[string-length() gt 7]">...</xsl:if>.
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