zoo/xts - 不能对 1-cell 子集进行数学运算?R 挂起 [英] zoo/xts - can't do math on 1-cell subsets? R hangs

问题描述

我在 Windows 上使用最新版本的 R/xts/zoo:R 2.15、xts 0.8-6、zoo 1.7-7

I'm using latest version of R/xts/zoo on Windows: R 2.15, xts 0.8-6, zoo 1.7-7

我看到了以下奇怪的行为，这在以前的版本中并非如此:

I'm seeing the following bizarre behavior, which was not the case with prior versions:

library(xts)
data(sample_matrix)
sample.xts <- as.xts(sample_matrix)

sample.xts[1, 2] - sample.xts[2,2]     # results in numeric(0)?!?!?!
(sample.xts[ 1, 2] - sample.xts[2,2])/sample.xts[3,1]  # if I run this twice R locks up

在这里，我将 XTS 对象子集化为单个单元格.减法不再有效.此外，除法导致 R 完全锁定.

Here I have subset an XTS object to a single cell. Subtraction no longer works. Also, division causes R to completely lock up.

还有人看到这个吗?这是一个已知的错误还是我遗漏了什么?我可以在两台机器上重现这个.

Does anyone else see this? Is this a known bug or am I missing something? I can reproduce this on two machines.

会话信息(一些包作为机密删除):

Session Info (a few packages deleted as confidential):

R version 2.15.0 (2012-03-30)
Platform: x86_64-pc-mingw32/x64 (64-bit)

locale:
[1] LC_COLLATE=English_United States.1252  LC_CTYPE=English_United States.1252    LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C                           LC_TIME=English_United States.1252    

attached base packages:
[1] parallel  stats     graphics  utils     datasets  grDevices methods   base     

推荐答案

您永远无法减去索引不重叠的 xts/zoo 对象.算术运算总是在执行运算之前合并.您需要使用 coredata 以便您编写的减法提供您期望的结果.

You never could subtract xts/zoo objects with non-overlapping indices. Arithmetic operations always merge before performing the operation. You need to use coredata in order for the subtraction you've written to provide the result you expect.

coredata(sample.xts[1,2]) - coredata(sample.xts[2,2])

我可以复制第二个问题，但我不确定这应该是解决的高优先级问题，因为它不符合 zoo/xts 习惯用法，并且会导致一个完全空的 xts 对象.如果(某些)索引对齐，一切都很好.

I can replicate the second issue but I'm not sure this should be a high priority to fix, because it doesn't fit the zoo/xts idiom and would result in a completely empty xts object. Everything is fine if (some of) the indices align.

(sample.xts[1,2] - sample.xts[1,3]) / sample.xts[1,4]
(sample.xts[2,2] - sample.xts[1:2,3]) / sample.xts[2:3,4]

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