从 Azure Pipeline .yaml 干净退出? [英] Clean Exit from an Azure Pipeline .yaml?

问题描述

是否有比让脚本抛出错误更好/更干净/更惯用的方法来退出基于 .yaml 的 Azure Pipeline?

Is there a better/cleaner/more idiomatic way to exit a .yaml-based Azure Pipeline than say having a script throw an error?

例如，这可行，但感觉很笨重:

e.g., this works but it feels clunky:

- task: PowerShell@2
  displayName: "Exit"
  inputs:
    targetType: 'inline'
    script: |
      throw 'Exiting';

推荐答案

- powershell: |
  write-host "##vso[task.complete result=Failed;]The reason you quit"

会更整洁，但仍会失败.

Would be neater, but would still fail the job.

没有等同于跳过剩余的工作，除非你有条件根据变量值跳过所有未来的任务:

There is no equivalent to skip the rest of the job, unless you work with conditions to skip all future tasks based on a variable value:

variables:
  skiprest: false

- powershell: |
  write-host "##vso[task.setvariable variable=skiprest]true"
- powershell:
  condition: and(succeeded(), eq(skiprest, 'false'))
- powershell:
  condition: and(succeeded(), eq(skiprest, 'false'))
- powershell:
  condition: and(succeeded(), eq(skiprest, 'false'))
- powershell:
  condition: and(succeeded(), eq(skiprest, 'false'))

您可以使用 YAML 迭代插入 从模板中应用该条件到我认为的工作中的所有任务.我手头没有工作示例，但文档显示了如何注入 dependsOn:，我想这个技巧非常相似:

You could use a YAML iterative insertion from a template to apply that condition to all tasks in a job I suppose. I don't have a working sample at hand, but the docs show how to inject a dependsOn:, the trick would be very similar I suppose:

# job.yml
parameters:
- name: 'jobs'
  type: jobList
  default: []

jobs:
- job: SomeSpecialTool                # Run your special tool in its own job first
  steps:
  - task: RunSpecialTool@1
- ${{ each job in parameters.jobs }}: # Then do each job
  - ${{ each pair in job }}:          # Insert all properties other than "dependsOn"
      ${{ if ne(pair.key, 'dependsOn') }}:
        ${{ pair.key }}: ${{ pair.value }}
    dependsOn:                        # Inject dependency
    - SomeSpecialTool
    - ${{ if job.dependsOn }}:
      - ${{ job.dependsOn }}

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