yii cdbcriteria:复杂的连接 [英] yii cdbcriteria: complex joins

问题描述

我最近使用 Yii 启动了一个项目，我正在尝试习惯查询构建器.现在，我想使用连接进行查询并访问查询中连接表的数据，但我无法使以下内容正常工作:

I recently started a project using Yii and I'm trying to get used to the query builder. Now, I want to make a query using joins and access the joining tables' data in the query but I haven't been able to get the following to work:

我的(简化的)数据库表:

My (simplified) db-tables:

客户(#id，姓名)
员工(#id，姓名)
customer_employee(#customerid, #employeeid)
会计(#id，customerid，started_date，finished_date，月，年)

customer(#id, name)
employee(#id, name)
customer_employee(#customerid, #employeeid)
accounting(#id, customerid, started_date, finished_date, month, year)

• 客户和员工之间的多对多关系
• 客户和会计之间的一对多关系

我想执行以下查询，它将选择与某个员工关联的所有客户并显示他们的会计状态(started_date &finished_date)(如果适用)(否则为 null).

I want to execute the following query, which would select all the customers associated with a certain employee and display their accounting status (started_date & finished_date) if applicable (otherwise null).

以下查询完美无缺，只是我无法让它与 cdbcriteria 和 Yii 查询构建器一起使用:(此外，硬编码 id 仅用于此示例)

The following query works perfectly, it's just that I can't get it to work with the cdbcriteria and Yii query builder: (also, hardcoded id is just for this example)

SELECT name, started_date, finished_date
FROM customer
RIGHT JOIN customer_employee ON customer.id=customer_employee.customerid
LEFT JOIN accounting ON customer.id=accounting.customerid
WHERE customer_employee.employeeid=2';

请帮忙！

推荐答案

1.创建命令

Yii::app()->db->createCommand()
  ->select('name, started_date, finished_date')
  ->from('customer c')
  ->rightJoin('customer_employee ce', 'c.id=ce.customerid')
  ->leftJoin('accounting a', 'c.id=a.customerid')
  ->where('ce.employeeid=:id', array(':id'=>2))
  ->queryRow();

2.CdbCriteria

2. CdbCriteria

$criteria = new CDbCriteria;
$criteria->select    = 'name, started_date, finished_date';
$criteria->join      = 'RIGHT JOIN customer_employee ON customer.id=customer_employee.customerid ';
$criteria->join     .= 'LEFT JOIN accounting ON customer.id=accounting.customerid';
$criteria->condition = 'customer_employee.employeeid=:id';
$criteria->params    = array(':id'=>2);

$customers = Customers::model()->find($criteria);

*.不要忘记规则:http://www.yiiframework.com/doc/guide/1.1/en/database.arr

我没有测试你的 SQL，但如果对你有用，这些应该也适用于 Yii.

I didn't tested your SQLs, but if worked for you, these should, also work in Yii.

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