YII 框架用户友好 URL [英] YII framework user friendly URL

问题描述

我的 yii PHP 项目有 UserController，它有一个名为 actionView 的操作.我可以使用以下 URL 访问用户查看页面

My yii PHP project has UserController and it has an action called actionView. I can access user view page using following URL

mysite.com/user/view/id/1

我想把那个改成

mysite.com/username

我该怎么做.

我知道我可以简单地创建规则来对用户更友好，以获取诸如

I know that i can simply create rule to be more user friendly to get url such as

mysite.com/user/username

但是以数据库资源名称作为直接参数 (mysite.com/username) 的 url 方案是完全不同的故事.

But url scheme with database resource name as direct param (mysite.com/username) is whole different story.

推荐答案

Url rule:

array(
    '<username:\w+>'=>'user/view',
)

请注意，在这种方案中，您还必须为所有控制器创建规则并将规则放在最后，因此最好以用户为前缀:

Note that in such scheme, you must also create rules for all your controllers and place above rule at the end, so better prefix it with user:

array(
    'user/<username:\w+>'=>'user/view',
)

结果 url 将是 example.com/user/username

在行动:

public function actionView($username) ...

更新:要创建对任何输入变量做出反应的规则，请创建自定义 url 规则类，以下是一些示例，请根据您的需要进行修改:

Update: To make rule which reacts on any input variable create custom url rule class, here is some example, modify to your needs:

class PageUrlRule extends CBaseUrlRule
{

        public function createUrl($manager, $route, $params, $ampersand)
        {
                // Ignore this rule for creating urls
                return false;
        }

        public function parseUrl($manager, $request, $pathInfo, $rawPathInfo)
        {
                // Ignore / url or any controller name - which could conflict with username
                if($pathInfo == '/')
                {
                        return true;
                }
                // Search for username or any resource in db
                // This is for mongo so it should be tuned to your db,
                // just check if username exists
                $criteria = new EMongoCriteria();
                $criteria->url->$lang = $url;
                $criteria->select(['_id']);
                $criteria->limit(1);
                $model = PageItem::model();
                $cursor = $model->findAll($criteria);
                // Create route, instead of $url id can be used
                $route = sprintf('content/page/view/url/%s', urlencode($url));
                // If found return route or false if not found
                return $cursor->count() ? $route : false;
        }

}

然后将此规则放在 urlmanager 配置的开头

Then place this rule in beginning of urlmanager config

'rules' => [
    [
        'class' => 'application.modules.content.components.PageUrlRule'
    ],
    // Other rules here

重要:如果用户的用户名与您的控制器相同，它将匹配用户名，控制器将无法访问.您必须禁止注册与控制器同名的用户.

Important: If user has username same as your controller, it will match username and controller will be inaccessible. You must forbid registering users with same names as controllers.

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