如何在yii2中显示关系数据 [英] How to show relational data in yii2

查看:27
本文介绍了如何在yii2中显示关系数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我无法理解 yii 2 中的关系是如何工作的

我在 mysql 数据库中有 2 个表,作者和书籍.

book 有一个名为 author 的列,它通过外键链接到 author 表的 id.

我已经使用 gii 生成了 CRUD,我希望作者姓名出现在列表视图中,以及创建和更新视图中作者姓名的下拉菜单中.

但即使在列表视图中,我似乎也无法使关系正常工作.

这是我的代码

图书模型:

11]];}/*** @inheritdoc*/公共函数attributeLabels(){返回 ['id' =>'ID','名称' =>'姓名','作者' =>'作者',];}公共函数 getAuthor(){返回 $this->hasOne(Author::className(), ['id' => 'author']);}}

图书搜索模型:

joinWith('author');$dataProvider = new ActiveDataProvider(['查询' =>$查询,]);var_dump($dataProvider);如果 (!$this->validate()) {//如果您不想在验证失败时返回任何记录,请取消注释以下行//$query->where('0=1');返回 $dataProvider;}$query->andFilterWhere(['id' =>$this->id,'作者' =>$this->作者,]);$query->andFilterWhere(['like', 'name', $this->name]);返回 $dataProvider;}}

此外,这是视图文件:

title = '书籍';$this->params['breadcrumbs'][] = $this->title;?><div class="book-index"><h1><?= Html::encode($this->title) ?></h1><?php//echo $this->render('_search', ['model' => $searchModel]);?><p><?= Html::a('Create Book', ['create'], ['class' => 'btn btn-success']) ?></p><?= GridView::widget(['数据提供者' =>$数据提供者,'过滤器模型' =>$搜索模型,'列' =>[['类' =>'yii\grid\SerialColumn'],'ID','姓名',['属性' =>'作者','价值' =>'作者名',],['类' =>'yii\grid\ActionColumn'],],]);?>

作者模型:

200]];}/*** @inheritdoc*/公共函数attributeLabels(){返回 ['id' =>'ID','名称' =>'姓名',];}}

我想我可能需要更改作者/作者搜索模型中的某些地方.

有人可以帮忙吗

谢谢

解决方案

您还可以使用匿名函数的值向 gridview 添加列,如下所述 http://www.yiiframework.com/doc-2.0/yii-grid-datacolumn.html#$value-detail.例如,您可以在 gridview 中像这样显示作者姓名:

[['属性'=>'作者.name','值'=> 函数($model,$key,$index,$column){返回 $model->author->name;},],//...其他列]);?>

您还可以像这样返回一个指向作者详细信息视图的 html 链接:

//...'列'=>[['属性'=>'作者','值'=> 函数($model,$key,$index,$column){return Html::a($model->author->name, ['/author/view', 'id'=>$model->author->id]);},],//...],//...

I'm having trouble understanding how relations work in yii 2

I have 2 tables in a mysql database, author and book.

book has a column named author which links to the id of the author table via foreign key.

I've generated CRUD using gii, and I want the author name to appear in the list view, as well as dropdowns for the author name in the create and update views.

But I cant seem to get the relation working even in the list view.

Here's my code

Book Model:

<?php

namespace app\models;

use Yii;
use app\models\Author;

/**
 * This is the model class for table "book".
 *
 * @property integer $id
 * @property string $name
 * @property integer $author
 */
class Book extends \yii\db\ActiveRecord
{
    /**
     * @inheritdoc
     */
    public static function tableName()
    {
        return 'book';
    }

    /**
     * @inheritdoc
     */
    public function rules()
    {
        return [
            [['name', 'author'], 'required'],
            [['author'], 'integer'],
            [['name'], 'string', 'max' => 11]
        ];
    }

    /**
     * @inheritdoc
     */
    public function attributeLabels()
    {
        return [
            'id' => 'ID',
            'name' => 'Name',
            'author' => 'Author',
        ];
    }

    public function getAuthor()
    {
        return $this->hasOne(Author::className(), ['id' => 'author']);
    }
}

BookSearch Model:

<?php

namespace app\models;

use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\Book;

/**
 * BookSearch represents the model behind the search form about `app\models\Book`.
 */
class BookSearch extends Book
{
    /**
     * @inheritdoc
     */
    public function rules()
    {
        return [
            [['id', 'author'], 'integer'],
            [['name'], 'safe'],
        ];
    }

    /**
     * @inheritdoc
     */
    public function scenarios()
    {
        // bypass scenarios() implementation in the parent class
        return Model::scenarios();
    }

    /**
     * Creates data provider instance with search query applied
     *
     * @param array $params
     *
     * @return ActiveDataProvider
     */
    public function search($params)
    {
        $query = Book::find();
        $query->joinWith('author');

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
        ]);

        var_dump($dataProvider);
        if (!$this->validate()) {
            // uncomment the following line if you do not want to return any records when validation fails
            // $query->where('0=1');
            return $dataProvider;
        }

        $query->andFilterWhere([
            'id' => $this->id,
            'author' => $this->author,
        ]);

        $query->andFilterWhere(['like', 'name', $this->name]);

        return $dataProvider;
    }
}

Also, here's the view file:

<?php

use yii\helpers\Html;
use yii\grid\GridView;

/* @var $this yii\web\View */
/* @var $searchModel app\models\BookSearch */
/* @var $dataProvider yii\data\ActiveDataProvider */

$this->title = 'Books';
$this->params['breadcrumbs'][] = $this->title;
?>
<div class="book-index">

    <h1><?= Html::encode($this->title) ?></h1>
    <?php // echo $this->render('_search', ['model' => $searchModel]); ?>

    <p>
        <?= Html::a('Create Book', ['create'], ['class' => 'btn btn-success']) ?>
    </p>

    <?= GridView::widget([
        'dataProvider' => $dataProvider,
        'filterModel' => $searchModel,
        'columns' => [
            ['class' => 'yii\grid\SerialColumn'],

            'id',
            'name',
            [
                'attribute' => 'author',
                'value'     => 'author.name',
            ],

            ['class' => 'yii\grid\ActionColumn'],
        ],
    ]); ?>

</div>

Author Model:

<?php

namespace app\models;

use Yii;

/**
 * This is the model class for table "author".
 *
 * @property integer $id
 * @property string $name
 */
class Author extends \yii\db\ActiveRecord
{
    /**
     * @inheritdoc
     */
    public static function tableName()
    {
        return 'author';
    }

    /**
     * @inheritdoc
     */
    public function rules()
    {
        return [
            [['name'], 'required'],
            [['name'], 'string', 'max' => 200]
        ];
    }

    /**
     * @inheritdoc
     */
    public function attributeLabels()
    {
        return [
            'id' => 'ID',
            'name' => 'Name',
        ];
    }


}

I think I may have to change something somehwhere in the author/authorSearch model.

Can someone help

thanks

解决方案

You can also add columns to a gridview with value from an anonymous function as described here http://www.yiiframework.com/doc-2.0/yii-grid-datacolumn.html#$value-detail. For example you can show an author's name like this in a gridview:

<?= GridView::widget([
'dataProvider'=>$dataProvider,
'filterModel'=>$searchModel,
'columns'=>[
    [
        'attribute'=>'author.name',
        'value'=>function ($model, $key, $index, $column) {
            return $model->author->name;
        },
    ],
    //...other columns
]);
?>

you can also return a html-link to the detail-view of an author like this:

//...
'columns'=>[
    [
        'attribute'=>'author',
        'value'=>function ($model, $key, $index, $column) {
            return Html::a($model->author->name, ['/author/view', 'id'=>$model->author->id]);
        },
    ],
    //...
],
//...

这篇关于如何在yii2中显示关系数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆