返回yii 2.0中指定AR类的静态模型 [英] Returns the static model of the specified AR class in yii 2.0
问题描述
我想使用 YII 2 构建博客应用程序,我使用 tbl_lookup 表来存储其他数据对象所需的整数值和文本表示之间的映射.我修改 Lookup 模型类如下,以便更轻松地访问表中的文本数据.这是我的代码:
i want to build blog application using YII 2, i use the tbl_lookup table to store the mapping between integer values and textual representations that are needed by other data objects. i modify the Lookup model class as follows to more easily access the textual data in the table. here my code :
<?php
namespace common\models;
use Yii;
?>
class Lookup extends \yii\db\ActiveRecord
{
private static $_items=array();
public static function tableName()
{
return '{{%lookup}}';
}
public static function model($className=__CLASS__)
{
return parent::model($className);
}
/**
* @inheritdoc
*/
public function rules()
{
return [
[['name', 'code', 'type', 'position'], 'required'],
[['code', 'position'], 'integer'],
[['name', 'type'], 'string', 'max' => 128]
];
}
/**
* @inheritdoc
*/
public function attributeLabels()
{
return [
'id' => 'ID',
'name' => 'Name',
'code' => 'Code',
'type' => 'Type',
'position' => 'Position',
];
}
private static function loadItems($type)
{
self::$_items[$type]=[];
$models=self::model()->findAll([
'condition'=>'type=:$type',
'params'=>[':type'=>$type],
'order'=>'position',
]);
foreach ($models as $model)
self::$_items[$type][$model->code]=$model->name;
}
public static function items($type)
{
if(!isset(self::$_items[$type]))
self::loadItems($type);
return self::$_items[$type];
}
public static function item($type, $code)
{
if(!isset(self::$_items[$type]))
self::loadItems ($type);
return isset(self::$_items[$type][$code]) ? self::$_items[$type][$code] : false;
}
}
但是当我想返回静态模型类时出现一些错误
but i get some error when i want to return the static model class
public static function model($className=__CLASS__)
{
return parent::model($className);
}
有人帮我吗?我的错在哪里.或者这里有人有一些使用 yii 2 制作博客应用程序的教程吗?谢谢.
does anyone to help me ? where's my mistake. or anyone here have some tutorial to make blog application using yii 2 ? thank you.
推荐答案
在 Yii2 中你不使用 model()
方法.因为,Yii2 和 Yii1 是不同的(更多见 https://github.com/yiisoft/yii2/blob/master/docs/guide/intro-upgrade-from-v1.md).在 Yii1 中提供这样的数据:
In Yii2 you don't use model()
method. Because, Yii2 and Yii1 is different(see more https://github.com/yiisoft/yii2/blob/master/docs/guide/intro-upgrade-from-v1.md). In Yii1 to provide data like that:
Post::model()->find($condition,$params);
在 Yii2 中提供这样的数据:
In Yii2 to provide data like that:
Post::find()->where(['type' => $id])->all();
查看更多https://github.com/yiisoft/yii2/blob/master/docs/guide/db-active-record.md
删除模型中的model
:
public static function model($className=__CLASS__)
{
return parent::model($className);
}
并将 loadItems
方法更改为:
private static function loadItems($type)
{
self::$_items[$type]=[];
$models=self::findAll([
'condition'=>'type=:$type',
'params'=>[':type'=>$type],
'order'=>'position',
]);
foreach ($models as $model)
self::$_items[$type][$model->code]=$model->name;
}
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