翻译查询以使用 Zend_Db_Select [英] Translating a query to use Zend_Db_Select

问题描述

我在翻译此查询以使用 ZF 的 Zend_Db_Select 时遇到一些问题:

I'm having some problems translating this query to use ZF's Zend_Db_Select:

SELECT b.id, b.title, b.description 
FROM memberships AS m
JOIN blogs AS b ON b.id = m.blog_id 
WHERE m.user_id = ? 
ORDER BY m.created
LIMIT 0, 30

(此查询有效并返回结果)

(this query works and returns results)

Memberships 是blogs 和users 之间的链接表.这是一个简单的 |身份证 |blog_id |user_id | 事情.

Memberships is a link table between blogs and users. It's a simple | id | blog_id | user_id | affair.

这是我目前所拥有的:

// $table = Zend_Db_Table instance, $id = a user id
$select = $table->select()
->from(array('m' => 'memberships'), array('b.id', 'b.title', 'b.description'))
->join(array('b' => 'blogs'), 'b.id = m.blog_id')
->where('m.user_id = ?', (int) $id)
->order('m.created DESC')
->limit(0, 30);

这是我遇到的(奇怪的(对我来说))错误:

This is the (strange (to me)) error I'm getting:

#0: 选择查询不能加入另一个表

发生在 D:\...\library\Zend\Db\Table\Select.php 的第 211 行.

Occurred on line 211 of D:\...\library\Zend\Db\Table\Select.php.

感谢您的帮助.

推荐答案

当从您的表对象中检索时，我认为该语句将仅限于该表.Zend_Db_Table::select() 方法返回一个 Zend_Db_Table_Select 对象，它是 Zend_Db_Select 的子类，并强加了这个限制.试试这个:

When retrieved from your table object, the statement will be limited to that table I think. The Zend_Db_Table::select() methods returns a Zend_Db_Table_Select object which is a subclass of Zend_Db_Select and imposes this restriction. Try this instead:

$db = Zend_Db::factory( ...options... );
$select = new Zend_Db_Select($adapter);
$select->from( 'my_table_name' )->join( ...

如果您愿意，以下内容应该是等效的:

If you prefer, the following should be equivalent:

$db = Zend_Db::factory( ...options... );
$db->select()->from( 'my_table_name' )->join( ...

这篇关于翻译查询以使用 Zend_Db_Select的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！