如何使用 Python 创建文件路径的 zip 文件，包括空目录? [英] How do I create a zip file of a file path using Python, including empty directories?

问题描述

我一直在尝试使用 zipfile 和 shutil.make_archive 模块递归地创建目录的 zip 文件.两个模块都工作得很好——除了空目录不会被添加到档案中.包含其他空目录的空目录也会被静默跳过.

I've been trying to use the zipfile and shutil.make_archive modules to recursively create a zip file of a directory. Both modules work great--except empty directories do not get added to the archive. Empty directories containing other empty directories are also silently skipped.

我可以使用 7Zip 创建相同路径的存档，并保留空目录.因此我知道这在文件格式本身中是可能的.我只是不知道如何在 Python 中做到这一点.有任何想法吗?谢谢！

I can use 7Zip to create an archive of the same path and empty directories are preserved. Therefore I know this is possible within the file format itself. I just don't know how to do it within Python. Any ideas? Thanks!

推荐答案

有一个使用 zipfile 的例子:

There is a example using zipfile:

import os, zipfile  
from os.path import join  
def zipfolder(foldername, filename, includeEmptyDIr=True):   
    empty_dirs = []  
    zip = zipfile.ZipFile(filename, 'w', zipfile.ZIP_DEFLATED)  
    for root, dirs, files in os.walk(foldername):  
        empty_dirs.extend([dir for dir in dirs if os.listdir(join(root, dir)) == []])  
        for name in files:  
            zip.write(join(root ,name))  
        if includeEmptyDIr:  
            for dir in empty_dirs:  
                zif = zipfile.ZipInfo(join(root, dir) + "/")  
                zip.writestr(zif, "")  
        empty_dirs = []  
    zip.close() 

if __name__ == "__main__":
    zipfolder('test1/noname/', 'zip.zip')

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