上传 Zip 文件并解压缩 Zip [英] Upload Zip File and Extract the Zip

问题描述

我有一个表单 (HTML)，它将文件提交给 PHP 脚本，该脚本将文件重命名为 ZIP，将其存储在一个文件夹中(随机名称)，然后提取该文件.

I have a form (HTML) which submits a file to a PHP script which renames the file to ZIP, stores it in a folder (random name) and then extracts that file.

文件已上传.该文件夹已正确创建.文件被正确重命名.

The file gets uploaded. The folder is created correctly. The file gets renamed correctly.

解压失败.

这是我的表格:

<form action="up.php" method="post" enctype="multipart/form-data" name="form1" id="form1">

Select file 
<input name="ufile" type="file" id="ufile" size="50" />

<input type="submit" name="Submit" value="Upload" />

 </form>

这里是 PHP 脚本 - up.php

Here is the PHP script - up.php

$file_name = $HTTP_POST_FILES['ufile']['name'];
$random_digit=rand(0000,9999);
$new_file_name=$random_digit.".zip";
mkdir($random_digit, 0777, true);

$path= $random_digit.'/'.$new_file_name;
if($ufile !=none)
 {
    if(copy($HTTP_POST_FILES['ufile']['tmp_name'], $path))
 {
 echo "The upload is successful<BR/>"; 
 echo "File Renamed to: ".$new_file_name." for processing.<BR/>"; 
 echo "File Size :".$HTTP_POST_FILES['ufile']['size']."<BR/>"; 
 echo "<strong><a style='color:#6A8DBC; text-decoration:none' href='".$link_address."'>Proceed to the next phase of the importation of data to the system</a></strong></br>";
  }
 else
  {
   echo "Error";
   }
 }

  $zip = new ZipArchive;
  $res = $zip->open($new_file_name);
  if ($res === TRUE) {
     $zip->extractTo($random_digit.'/');
     $zip->close();
     echo 'extraction successful';
     } else {
     echo 'extraction error';
     }

是不是文件夹的模式阻止了提取?据我所知，没有语法错误.

Is it the mode of the folder which prevents extraction? As far as I can see, there is no syntax error.

推荐答案

try

$res = $zip->open($path)

当您将文件移动到 $path 后，您需要对位于 $path

As you have moved the file to $path you then need to operate on the file at $path

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