Swift:解压文件 [英] Swift: unzipping file

问题描述

我正在尝试使用本机 libcompression 库从 zip 文件中的 txt 文件中获取 String.其实我使用的代码来自

I’m trying to get String from txt file inside the zip file using native libcompression library. Actually I use the code from

• https://github.com/mw99/DataCompression/blob/master/Sources/DataCompression.swift.

起初，我在做:

let zip = try? Data(contentsOf: "/.../test.zip")    
let tmp: Data? = zip?.unzip()
let txt: String? = String(data: tmp!, encoding: .utf8)

但是我如何获取 zip 文件的内容以及如何从某个 txt 文件中获取数据?

But how do I get the contents of zip file and how do I get data from certain txt file?

推荐答案

ZIP Foundation 支持访问个人ZIP 档案中的条目.
您必须通过将文件 URL 传递给 Archive 初始化程序来初始化存档.
之后，您可以通过下标访问特定条目:

ZIP Foundation supports accessing individual entries in ZIP archives.
You have to initialize an archive by passing a file URL to the Archive initializer.
Afterwards you can access a specific entry via subscripting:

let fileManager = FileManager()
let currentWorkingPath = fileManager.currentDirectoryPath
var archiveURL = URL(fileURLWithPath: currentWorkingPath)
archiveURL.appendPathComponent("test.zip")
guard let archive = Archive(url: archiveURL, accessMode: .read) else  {
    return
}
guard let entry = archive["file.txt"] else {
    return
}
var destinationURL = URL(fileURLWithPath: currentWorkingPath)
destinationURL.appendPathComponent("out.txt")
do {
    try archive.extract(entry, to: destinationURL)
} catch {
    print("Extracting entry from archive failed with error:\(error)")
}

您还可以使用基于闭包的 API 直接访问 entry 的内容.这允许您处理条目而无需先将其写入文件系统:

You can also directly access the contents of entry by using the closure based API. This allows you to process the entry without writing it to the file system first:

try archive.extract(entry, consumer: { (data) in
    print(data.count)
})

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